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Svetach [21]
2 years ago
7

I'm studying the equilibrium of forces so hard that I got confused for a sec. Is the force due to gravity included in summing up

moments about a point? Or external forces are only considered in the summation of moments? Thanks!
Physics
1 answer:
jenyasd209 [6]2 years ago
3 0

Answer:

Yes, you would consider the mass × gravity at the centre of gravity of the object in question to cause a moment, hence it should be included in your resolution

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When you ride a bike and make a turn, you can feel your body trying to move in the same direction the bike was going. Which of N
Alisiya [41]

Answer:

C

Explanation:

Newtons second law explains this the most because for every action their is an equal and opposite reaction. The reaction of you turning, causes the reaction of your whole body to turn with the bike.

3 0
3 years ago
Which best describes the electric field created by a positive charge?
Vlad [161]
Its rays point away from the charge
3 0
3 years ago
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A ball is released from a hot air balloon moving downward with a velocity of -10.0 meters/second and a height of 1,000 meters. H
Nikolay [14]
Here, ball is released... and it is in free fall means with zero initial velocity.

We know, s = ut + 1/2 at²
Here, s = 1000 m
u = 0
a = 10 m/s2

Substitute their values, 
1000 = 0 + 1/2 * 10 * t²
2000 = 10 * t²
t² = 2000 /10
t = √200
t = 14.14 s

In short, Your Answer would be 14.14 seconds

Hope this helps!
7 0
3 years ago
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A car with a mass of 1380 Kg is traveling at 23 m/s to the north. A truck with a mass of 1625 Kg is traveling at 26 m/s to the s
trasher [3.6K]

Answer: -3.49 m/s (to the south)

Explanation:

This problem can be solved by the Conservation of Momentum principle which establishes the initial momentum p_{i} must be equal to the final momentum p_{f}, and taking into account this is aninelastic collision:

Before the collision:

p_{i}=mV_{o}+MU_{o} (1)

After the collision:

p_{f}=(m+M)V_{f} (2)

Where:

m=1380 kg is the mass of the car

V_{o}=23 m/s is the velocity of the car, directed to the north

M=1625 kg is the mass of the truck

U_{o}=-26 m/s is the velocity of the truck, directed to the south

V_{f} is the final velocity of both the car and the truck

p_{i}=p_{f} (3)

mV_{o}+MU_{o}=(m+M)V_{f} (4)

Isolating V_{f}:

V_{f}=\frac{mV_{o}+MU_{o}}{m+M} (5)

V_{f}=\frac{(1380 kg)(23 m/s)+(1625 kg)(-26 m/s)}{1380 kg+1625 kg} (6)

Finally:

V_{f}=-3.49 m/s The negative sign indicates the direction of the velocity is to the south

8 0
3 years ago
If two vectors are perpendicular to each other, how should you add them?
Aleksandr [31]

Let us consider two vectors A and B.

As per the question, the two vectors are perpendicular to each other.

Hence the angle between them  \theta =90 degree

We are asked to calculate the resultant of these two vectors.

As per parallelogram law of vector addition, the resultant of two vectors are-

                      R=\sqrt{A^{2}+ B^{2}+2ABcos\theta

                                =\sqrt{ A^{2}+ B^{2}+2AB*cos90}    [cos90=0]

                                =\sqrt{ A^{2}+ B^{2}

This is the way by which we can add two perpendicular vectors.


8 0
3 years ago
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