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mina [271]
3 years ago
14

A jet plane comes in for a downward dive as shown in the figure below.

Physics
2 answers:
xxTIMURxx [149]3 years ago
8 0

The solution would be like this for this specific problem:

<span>5.5 g = g + v^2/r </span><span>
<span>4.5 g = v^2/r </span>
<span>v^2 = 4.5 g * r </span>
<span>v = sqrt ( 4.5 *9.81m/s^2 * 350 m) </span>
v = 124 m/s</span>

So the pilot will black out for this dive at 124 m/s. I am hoping that these answers have satisfied your query and it will be able to help you in your endeavors, and if you would like, feel free to ask another question.

wlad13 [49]3 years ago
8 0

As we know that centripetal acceleration during circular motion is given by the formula

a = \frac{v^2}{R}

as we know that maximum value of acceleration is given as

a = 5.50 g

here we know that

g = 9.81 m/s^2

so here we will have

a = 5.50 (9.81 m/s^2)

a = 54 m/s^2

now we will have from above first equation

54 = \frac{v^2}{R}

54 = \frac{v^2}{350}

v = 137.4 m/s

so maximum possible speed will be 137.4 m/s

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goblinko [34]

Hence ,From the Guide there are other parameters which with this equation will give the exact time the athlete's walk back

T=\frac{d}{1.50}

From the question we are told

If the average velocity during the athlete's walk back  to the starting line in Guided Example 2.5 is – 1.50 m/s,

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Therefore

T=\frac{d}{1.50}

Hence ,From the Guide there are other parameters which with this equation will give the exact time the athlete's walk back

T=\frac{d}{1.50}

For more information on this visit

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The answer is a.) the ocean is colder than the land.
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Question 2 of 10
tangare [24]

Explanation:

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dezoksy [38]

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<h3>What is work done?</h3>

Work done is defined as the product of force and the distance moved by the force.

Mathematically:

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The work done by the force = 20 * 1000 = 20000J

The work done is positive and is equal to 20000 J

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Answer:

Explanation:

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