The volume of the object must be no larger than 
.
Explanation:
In order for an object to be able to float in water, its density must be equal or smaller than the water density.
The density of water is:
This means that the density of the object must be no larger than this value.
We also know that the density of an object is given by
where
m is the mass of the object
V is its volume
For the object in this problem, the mass is
Therefore, we can re-arrange the equation to find its volume:
So, the volume of the object must be no larger than .
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The value of parameter C for the function in the figure is 2.
<h3>What is amplitude of a wave?</h3>
The amplitude of a wave is the maximum displacement of the wave. It can also be described at the maximum upward displacement of a wave curve.
f(x) = Acos(x - C)
where;
- A is amplitude of the wave
- C is phase difference of the wave
<h3>What is angular frequency of a wave?</h3>
Angular frequency is the angular displacement of any element of the wave per unit time.
From the blue colored graph; at y = 1, x = -2 cm
1 = cos(2 - C)
(2 - C) = cos^(1)
(2 - C) = 0
C = 2
Thus, the value of parameter C for the function in the figure is 2.
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Force required is 100 N
<u>Given that;</u>
Rate of acceleration = 5 m/s²
Mass of object = 20kg
<u>Find:</u>
Force required
<u>Computation:</u>
Force = Mass × Acceleration
Force required = Rate of acceleration × Mass of object
Force required = 20 × 5
Force required = 100 N
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Well if you didn't you could make mistakes, which would lead ,in the best case, at a fail of the circuit , or if it goes out of control it could be dangerous
for example you have to know that the wires become hot and they loose their abbilitys as connecters(the hotter it will, the more energy you lose becouse the R will be bigger)
Answer:
(i) 
, (ii) 
, (iii)
Explanation:
(i) 
and 
represent the points where particle has a velocity of zero and spring reach maximum deformation, Given the absence of non-conservative force and by the Principle of Energy Conservation, the position where particle is at maximum speed is average of both extreme positions:
(ii) Maximum accelerations is reached at and .
(iii) Greatest net forces exerted on the particle are reached at and .
