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Galina-37 [17]
3 years ago
7

A planet has two

Physics
1 answer:
lozanna [386]3 years ago
7 0
Kepler's third law hypothesizes that for all the small bodies in orbit around the
same central body, the ratio of (orbital period squared) / (orbital radius cubed)
is the same number.

<u>Moon #1:</u>  (1.262 days)² / (2.346 x 10^4 km)³

<u>Moon #2:</u>  (orbital period)² / (9.378 x 10^3 km)³

If Kepler knew what he was talking about ... and Newton showed that he did ...
then these two fractions are equal, and may be written as a proportion.

Cross multiply the proportion:

(orbital period)² x (2.346 x 10^4)³ = (1.262 days)² x (9.378 x 10^3)³

Divide each side by (2.346 x 10^4)³:

(Orbital period)² = (1.262 days)² x (9.378 x 10^3 km)³ / (2.346 x 10^4 km)³

               =  0.1017 day²

Orbital period = <u>0.319 Earth day</u> = about 7.6 hours.
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Suppose you are standing at the exact center of a park surrounded by a circular road. An ambulance drives completely around this
vladimir2022 [97]

Answer: The pitch of the sound does not change.

Explanation: The pitch of sound wave is dependent on the frequency of the sound wave. The frequency of sound wave when their is a relative motion between an observer and a source is given by Doppler effect.

Doppler effect is a mathematical equation that gives the relationship between the observed frequency by an observer from any sound source and the relative motion between the observer and the source.

Mathematically,

f'= (v+v') /(v-vs) * f

Where f' = observed frequency of sound wave

v= speed of sound in air

v'= velocity of observer relative to sound source

vs= velocity of sound source relating to observer

f= frequency of sound produced by source

The observer is at the center, thus the distance between the observer and the source is constant (according to mensuration, the radius is constant for any given circle and since the car is moving along a circular path and the observer is at the center, thus the distance between them is constant), thus making the relative velocity between the observer and the source constant (vs=constant).

Also the frequency of sound wave produce by the source is a constant (f=constant)

The speed of sound in air is also a constant (v=336m/s)

The observer is standing at the center thus he is not moving, hence the relative motion between observer and source is also constant (v'=constant)

Since all parameters are constant, then the observed frequency will be constant too.



4 0
3 years ago
What do electric forces between charges depend on?
bonufazy [111]

Electrostatic forces between charges depend on the product of
the sizes of the charges, and the distance between them.

We should also mention the item about whether the charges are
both the same sign or opposite signs.  That determines whether
the forces will pull them together or push them apart, which is a
pretty significant item.

6 0
3 years ago
Read 2 more answers
Which one?? please someone quick!​
LiRa [457]

Answer:

i think its second law of motion.

Explanation:

4 0
3 years ago
Read 2 more answers
What is the unit of measurement for expressing the intensity of sound
Irina18 [472]
Decibel - the decibel is a relative unit of measurement equal to one 10th of a bel
5 0
2 years ago
A child\'s top is held in place, upright on a frictionless surface. The axle has a radius of r = 2.96 mm. Two strings are wrappe
sladkih [1.3K]

Answer:

Explanation:

Given

radius r=2.96 mm

Tension T=2.4 N

time taken=0.74 s

Let \alphabe the angular acceleration

2 T\times r=I\times \alpha

2\times 2.4\times 2.96\times 10^{-3}=0.5\times m\times (2.96\times 10^{-3})^2\times \alpha

\alpha =\frac{4\times 2.4}{m\times 2.96\times 10^{-3}}

\alpha =\frac{3.24\times 10^3}{m} rad/s^2

\omega =\omega _0+\alpha \cdot t

\omega =0+\frac{3.24\times 10^3}{m}\times 0.74

\omega =\frac{2.4\times 10^3}{m} rad/s

Angular momentum

L=I\omega

L=0.5\times mr^2\times \omega

L=0.5\times m\times (2.96\times 10^{-3})^2\times \frac{2.4\times 10^3}{m}

L=0.01051 kg-m^2/s

4 0
3 years ago
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