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3 years ago

A planet has two

1 answer:

7 0

Kepler's third law hypothesizes that for all the small bodies in orbit around the
same central body, the ratio of (orbital period squared) / (orbital radius cubed)
is the same number.

Moon #1: (1.262 days)² / (2.346 x 10^4 km)³

Moon #2: (orbital period)² / (9.378 x 10^3 km)³

If Kepler knew what he was talking about ... and Newton showed that he did ...
then these two fractions are equal, and may be written as a proportion.

Cross multiply the proportion:

(orbital period)² x (2.346 x 10^4)³ = (1.262 days)² x (9.378 x 10^3)³

Divide each side by (2.346 x 10^4)³:

(Orbital period)² = (1.262 days)² x (9.378 x 10^3 km)³ / (2.346 x 10^4 km)³

= 0.1017 day²

Orbital period = 0.319 Earth day = about 7.6 hours.

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Calculate the acceleration due to gravity on the moon. the moon's radius is 1.74×106m and its mass is 7.35×1022 kg.

Kaylis [27]

184.44

7,511.7 that s the answer

7 0

3 years ago

If you chip your tooth enamel, it may grow back. True False

Yuri [45]

Answer:

When a patient has a chipped tooth, it means that a small portion of their tooth is no longer there. Chipped teeth are one of the more common types of dental problems that general dentists deal with. However, chipped teeth do not grow back on any portion of a tooth and instead need to be repaired by a general dentist.

Hope this helped <3

5 0

3 years ago

Read 2 more answers

A plane wave with a wavelength of 500 nm is incident normally ona single slit with a width of 5.0 × 10–6 m.Consider waves that r

kaheart [24]

To solve this exercise it is necessary to use the concepts related to Difference in Phase.

The Difference in phase is given by

$\Phi = \frac{2\pi \delta}{\lambda}$

Where

$\delta =$ Horizontal distance between two points

$\lambda =$ Wavelength

From our values we have,

$\lambda = 500nm = 5*10^{-6}m$

$\theta = 1\°$

The horizontal distance between this two points would be given for

$\delta = dsin\theta$

Therefore using the equation we have

$\Phi = \frac{2\pi \delta}{\lambda}$

$\Phi = \frac{2\pi(dsin\theta)}{\lambda}$

$\Phi = \frac{2\pi(5*!0^{-6}sin(1))}{500*10^{-9}}$

$\Phi= 1.096 rad \approx = 1.1 rad$

Therefore the correct answer is C.

6 0

3 years ago

I need help for a review sheet

siniylev [52]

Tin is Sn, atomic number 47 is Silver, Mass of sodium is 22.9 u

3 0

3 years ago

You are studying a population of flowering plants for several years. When you present your research findings you make the statem

Anit [1.1K]

Answer:

Option A

Explanation:

The graph for this problem must depict the following ""Increased allocation of resources to reproduction relative to growth diminished future fecundity."

Hence, the survivor ship must be on the Y axis and the resources on the X axis.

Here the resources include the number of seeds produced.

hence, the higher is the number of seeds (resource), the lower is the survivorship (future fecundity)

Hence, option A is correct

6 0

3 years ago