Answer:
The velocity of the boat after the batman lands in it is +9.26 m/s
Explanation:
Applying the law of conservation of momentum,
Total momentum before collision = Total momentum after collision.
Note: The collision between the Batman and the boat is an inelastic collision.
m'u'+mu = V(m+m').................... Equation 1
Where m' = mass of the Batman, u' = initial velcoity of the batman, m = mass of the boat, u = initial velocity of the boat, V = common velocity.
make V the subject of equation 1
V = (m'u'+mu)/(m+m')............... Equation 2
Given: m' = 96.1 kg, u' = 0 m/s, m = 458 kg, u = +11.3 m/s.
Substitute these values into equation 2
V = [(96.1×0)+(458×11.2)]/(96.1+458)
V = 5129.6/554.1
V = +9.26 m/s
