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3 years ago

PLZ HELP ASAP LAST SIMMILAR TRIANGLES

Mathematics

2 answers:

igor_vitrenko [27]3 years ago

8 0

QR/KL=PQ/JK=PR/JL
t/1.5=25/5=22.5/4.5
t/1.5=5=5
t/1.5=5
solving for t:
1.5(t/1.5)=1.5(5)
t=7.5

Answer: t=7.5

Viktor [21]3 years ago

7 0

By similarity of triangles we have the following relationship:

(t) / (22.5) = (1.5) / (4.5)

Clearing the value of t we have:

t = ((1.5) / (4.5)) * 22.5

Simplifying we have:

t = ((1) / (3)) * 22.5

The value of t is:

T = 7.5

Answer:

T = 7.5

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4 years ago

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Priya has planted a garden shaped like a right triangle. She knows that one leg of the triangle is 11 meters long and that the a

olga55 [171]

Answer:

She will need 41.22 meters.

Step-by-step explanation:

She knows that one leg of the triangle is 11 meters long and that the angle formed by that leg and the hypotenuse is 50 degrees .

The leg is adjacent to the hypothenuse. We know that the cosine of an angle $\theta$ is given by:

$\cos{\theta} = \frac{l}{h}$

In which l is the length of the adjacent side and h is the hypothenuse.

Considering that we have $\theta = 50, l = 11$ , we can find the hypothenuse.

Looking at a calculator, the cosine of 50 degrees is 0.6428.

$0.6428 = \frac{11}{h}$

$0.6428h = 11$

$h = \frac{11}{0.6428}$

$h = 17.11$

The other leg:

In a right triangle, with legs $l_1$ and $l_2$ , and hypothenuse h, the pythagorean theorem states that:

$l_1^2 + l_2^2 = h^2$

We already have one of the legs and the hypothenuse, so:

$11^2 + l^2 = 17.11^2$

$l^2 = 17.11^2 - 11^2$

$l = \sqrt{17.11^2 - 11^2}$

$l = 13.11$

How many meters will she need?

This is the perimeter of the garden, which is the sum of its dimensions, of 11 meters, 13.11 meters and 17.11 meters. So

$P = 11 + 13.11 + 17.11 = 41.22$

She will need 41.22 meters.

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