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guapka [62]
3 years ago
11

PLZ HELP ASAP LAST SIMMILAR TRIANGLES

Mathematics
2 answers:
igor_vitrenko [27]3 years ago
8 0
QR/KL=PQ/JK=PR/JL
t/1.5=25/5=22.5/4.5
t/1.5=5=5
t/1.5=5
solving for t:
1.5(t/1.5)=1.5(5)
t=7.5

Answer: t=7.5

Viktor [21]3 years ago
7 0

<span>By similarity of triangles we have the following relationship:</span>

<span> (t) / (22.5) = (1.5) / (4.5)</span>

<span> Clearing the value of t we have:</span>

<span> t = ((1.5) / (4.5)) * 22.5</span>

<span> Simplifying we have:</span>

<span> t = ((1) / (3)) * 22.5</span>

<span> The value of t is:</span>

<span> T = 7.5</span>

<span> Answer:</span>

<span> <span>T = 7.5</span></span>

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I only need help with the second part of this question. please can you help?
matrenka [14]

13,822 to one significant figure is 10,000

623 to one significant figure is 600

14 to one significant figure is 10

10,000 times 600 = 6,000,000

6,000,000/10 = 600,000

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Lapatulllka [165]
Area would be 4.52 A= pi x radius squared
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4 0
3 years ago
Supervisor a earns a flat rate of $25 per hour, while supervisor b earns $20 per hour for the first 30 hours and then 50% more f
mixas84 [53]
Let same number of hours = x, 
since the salary earned is also the same, then
Salary of supervisor A = $25x
Salary of supervisor B = $20(30)+$30(x-30)
Equating
25x=600+30(x-30)
30x-25x=900-600
5x=300
x=60 hours
Check:
Salary of supervisor A = 25*60=1500
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3 years ago
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olga2289 [7]

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Step-by-step explanation:

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Find a polynomial with integer coefficients that satisfies the given conditions. R has degree 4 and zeros 3 − 3i and 2, with 2 a
dolphi86 [110]

Answer:

The required polynomial is P(x)=x^4-10x^3+46x^2-96x+72.

Step-by-step explanation:

If a polynomial has degree n and c_1,c_2,...,c_n are zeroes of the polynomial, then the polynomial is defined as

P(x)=a(x-c_1)(x-c_2)...(x-x_n)

It is given that the polynomial R has degree 4 and zeros 3 − 3i and 2. The multiplicity of zero 2 is 2.

According to complex conjugate theorem, if a+ib is zero of a polynomial, then its conjugate a-ib is also a zero of that polynomial.

Since 3-3i is zero, therefore 3+3i is also a zero.

Total zeroes of the polynomial are 4, i.e., 3-3i, 3_3i, 2,2. Let a=1, So, the required polynomial is

R(x)=(x-3+3i)(x-3-3i)(x-2)(x-2)

R(x)=((x-3)+3i)((x-3)-3i)(x-2)^2

R(x)=(x-3)^2-(3i)^2((x-3)-3i)(x-2)^2     [a^2-b^2=(a-b)(a+b)]

R(x)=(x^2-6x+9-9(i)^2((x-3)-3i)(x-2)^2

R(x)=(x^2-6x+18)(x^2-4x+4)                [i^2=-1]

R(x)=(x^2-6x+18)(x^2-4x+4)

R(x)=x^4-10x^3+46x^2-96x+72

Therefore the required polynomial is P(x)=x^4-10x^3+46x^2-96x+72.

3 0
3 years ago
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