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guapka [62]
3 years ago
11

PLZ HELP ASAP LAST SIMMILAR TRIANGLES

Mathematics
2 answers:
igor_vitrenko [27]3 years ago
8 0
QR/KL=PQ/JK=PR/JL
t/1.5=25/5=22.5/4.5
t/1.5=5=5
t/1.5=5
solving for t:
1.5(t/1.5)=1.5(5)
t=7.5

Answer: t=7.5

Viktor [21]3 years ago
7 0

<span>By similarity of triangles we have the following relationship:</span>

<span> (t) / (22.5) = (1.5) / (4.5)</span>

<span> Clearing the value of t we have:</span>

<span> t = ((1.5) / (4.5)) * 22.5</span>

<span> Simplifying we have:</span>

<span> t = ((1) / (3)) * 22.5</span>

<span> The value of t is:</span>

<span> T = 7.5</span>

<span> Answer:</span>

<span> <span>T = 7.5</span></span>

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Write the equation of a line that meets all the following requirements:
LuckyWell [14K]

9514 1404 393

Answer:

  • x + y = 5
  • y = -x + 5

Step-by-step explanation:

We can start with the point-slope form of the equation for a line. To meet the given requirements, we can use a point of (5, 0) and a slope of -1. Then the equation in that form is ...

  y -0 = -1(x -5)

Simplifying gives the slope-intercept form:

  y = -x +5 . . . . . . . use the distributive property to eliminate parentheses

Adding x to both sides gives the standard form:

  x + y = 5

__

<em>Explanation</em>

We know the line has the required intercept and slope because we chose those values to put into the point-slope form. Conversion from one form to another made use of the rules of equality, the additive identity element (y-0=y), and the distributive property.

8 0
3 years ago
Will give brainliest to correct answer​
likoan [24]

The answer is B

hope that helps

3 0
3 years ago
Please answer this correctly
Illusion [34]

Answer:

$15.50

Step-by-step explanation:

0.5 (1) + 5 (3)

0.5 + 15

15.50

7 0
3 years ago
In AOPQ , the measure of angle Q=90^ , OQ = 33, PO = 65 , and QP = 56 What ratio represents the tangent of angle P ?
ladessa [460]
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4 0
3 years ago
What simple interest rate would allow $6000 to grow to an amount of $14550 in 10 years?
Harman [31]

Answer:

\boxed{ \bold{ \huge{  \boxed{ \sf{ \: 14.25 \: \% \: }}}}}

Step-by-step explanation:

Given,

Principal ( P ) = $ 6000

Amount ( A ) = $ 14550

Time ( T ) = 10 years

Rate ( R ) = ?

<u>Finding </u><u>the </u><u>Interest</u>

The sum of principal and interest is called an amount.

From the definition,

\boxed{ \sf{Amount =  \: Principal + Interest}}

plug the values

⇒\sf{14550 = 6000 + Interest}

Swap the sides of the equation

⇒\sf{6000 + Interest = 14550}

Move 6000 to right hand side and change its sign

⇒\sf{Interest = 14550 - 6000}

Subtract 6000 from 14550

⇒\sf{Interest = \: 8550 \: }

Interest = $ 8550

<u>Finding </u><u>the </u><u>rate </u>

{ \boxed{ \sf{Rate =  \frac{Interest \times 100}{Principal \times Time}}}}

plug the values

⇒\sf{ Rate = \frac{8550  \times 100}{6000 \times 10} }

Calculate

⇒\sf{Rate =  \frac{855000}{60000} }

⇒\sf{Rate = 14.25 \: \% \: }

Hope I helped!

Best regards!!

8 0
3 years ago
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