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3 years ago

Which compound does H2SO4 represent when in an aqueous solution

Chemistry

2 answers:

WARRIOR [948]3 years ago

7 0

Answer: H₂SO₄ is the chemical formula that represents sulfuric acid.

Explanation:

1) H stands for hydrogen and H₂ means that each unit contains two atoms of hydrogen.

2) S stands for sulfur. Since there is not subscript, means each unit contains one atom of sulfur.

3) O stands for oxygen, and O₄ means that each unit has four oxygen atoms.

4) The way the compound is build up is the S atom at the center with two double bonds to each to one atom of O, and two single bonds one to each OH ion.

5) Sulfuric acid is a strong acid, so it dissociates in water and alghough the formula H₂SO₄ is used to represent it, the aqueous solution is formed by ions: HSO₃⁻, H⁺, SO₄²⁻, and OH⁻, as represented by these dissociation equaitons show:

1) H₂SO₄ ⇄H⁺ + HSO₄⁻ first dissociation

2) HSO₄⁻ ⇄ H⁺ + SO₄²⁻ second dissociation

So, H₂SO₄ is one form to represent sulfuric acid.

Valentin [98]3 years ago

5 0

Answer:

B. Sulfuric Acid

Explanation:

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In this case, according to the given information about the oxidation numbers anf the compounds given, it turns out possible to figure out the oxidation number of manganese in both MnI2, manganese (II) iodide and MnO2, manganese (IV) oxide, by using the concept of charge balance.

Thus, we can define the oxidation state of iodine and oxygen as -1 and -2, respectively, since the former needs one electron to complete the octet and the latter, two of them.

Next, we can write the following $x$ , since manganese has five oxidation states, and it is necessary to calculate the appropriate ones:

$Mn^xI_2^-\\\\Mn ^xO_2^{-2}$

Next, we multiply each anion's oxidation number by the subscript, to obtain the following:

$Mn^xI_2^-\rightarrow x-2=0;x=+2\\\\Mn ^xO_2^{-2}\rightarrow x-4=0;x=+4$

Thus, the correct choice is Manganese has an oxidation number of +2 in Mnl2 and +4 in MnO2.

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3 years ago

Select the pair that consists of a base and its conjugate acid in that order. CO32−/CO22−

lana [24]

Answer: The pair that consists of a base and its conjugate acid in that order. $NH_3/NH_4^+$

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

$H_3PO_4\rightarrow H_PO_4{2^-}+2H^+$

$H_2CO_3\rightarrow HCO_3^-+H^+$

$NH_3+H^+\rightarrow NH_4^+$

$HCO_3^-\rightarrow CO_3^{2-}+H^+$

$NH_3$ is gaining a proton, thus it is considered as a brønsted-lowry base and after gaining a proton, it forms $NH_4^+$ which is a conjugate acid.

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3 years ago

Which of the quantum numbers relate(s) to the electron only? Which relate(s) to the orbital?

olganol [36]

Answer:

Schrodinger's proposal, considered as the 5th atomic model, is to describe the characteristics of all the electrons in an atom, and for this I use what we know as quantum numbers.

Quantum numbers are called with the letters n, m, l and s and indicate the position and energy of the electron. No electron of the same atom can have the same quantum numbers.

Explanation:

n = main quantum number, which indicates the level of energy where the electron is, assumes positive integer values, from 1 to 7 and it is related to the orbital too.

I = secondary quantum number, which indicates the orbital in which the electron is located, can be s, p, d and f (0, 1, 2 and 3).

m = magnetic quantum number, represents the orientation of the orbitals in space, or the type of orbital, within a specific orbital. Assumes values of the negative secondary quantum number (-l) through zero, to the positive quantum number (+ l).

s = quantum number of spin, which describes the orientation of the electron spin. This number takes into account the rotation of the electron around its own axis as it moves around the nucleus. Assumes only two values +1/2 and - 1/2

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