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3 years ago

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What type of bonding does Sodium Sulphate comes under?and explain in detail please

1 answer:

natka813 [3]3 years ago

7 0

Answer:

<em>The</em><em> </em><em>bond </em><em>between</em><em> </em><em>sodium</em><em> </em><em>sulfate</em><em> </em><em>is </em><em>an </em><em>ionic</em><em> </em><em>bond </em><em>since </em><em>it's </em><em>a </em><em>bond </em><em>between</em><em> </em><em>a </em><em>metal </em><em>and </em><em>non </em><em>metals</em><em> </em><em>however</em><em> </em><em>the </em><em>bond </em><em>between</em><em> </em><em>sulfur</em><em> </em><em>and </em><em>oxygen</em><em> </em><em>is </em><em>a </em><em>covalent</em><em> </em><em>bond</em><em> </em><em>since</em><em> </em><em>the </em><em>two </em><em>are </em><em>non </em><em>metals </em><em>and </em><em>the </em><em>other </em><em>reason</em><em> </em><em>that </em><em>makes </em><em>this </em><em>an </em><em>ionic</em><em> </em><em>bond</em><em> </em><em>is </em><em>that </em><em>there </em><em>is </em><em>both </em><em>losing</em><em> </em><em>and </em><em>gaining</em><em> </em><em>of </em><em>electrons</em><em>.</em><em>.</em>

<em>I </em><em>hope </em><em>this </em><em>helps</em>

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3 years ago

What is the mean free path for the molecules in an ideal gas when the pressure is 100 kPa and the temperature is 300 K given tha

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The mean free path = 2.16*10^-6 m

Explanation:

<u>Given:</u>

Pressure of gas P = 100 kPa

Temperature T = 300 K

collision cross section, σ = 2.0*10^-20 m2

Boltzmann constant, k = 1.38*10^-23 J/K

<u>To determine:</u>

The mean free path, λ

<u>Calculation:</u>

The mean free path is related to the collision cross section by the following equation:

$\lambda =\frac{1}{n\sigma }------(1)$

where n = number density

$n = \frac{P}{kT}-----(2)$

Substituting for P, k and T in equation (2) gives:

$n = \frac{100,000 Pa}{1.38*10^{-23} J/K*300K} =2.42*10^{25}\ m^{3}$

Next, substituting for n and σ in equation (1) gives:

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3 years ago

Calculate the number of atoms in 5 moles H₂O.

oksano4ka [1.4K]

Answer:

90.35 × 10²³ atoms

Solution:

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