Michael has 3 quarters, 2 dimes, and 3 nickels in his pocket. He randomly draws two coins from his pocket, one at a time, and th

Question

Fed [463]

3 years ago

14

Michael has 3 quarters, 2 dimes, and 3 nickels in his pocket. He randomly draws two coins from his pocket, one at a time, and th

ey are both dimes. He says the probability of that occurring is 1 4 because 2 of the 8 coins are dime

Mathematics

2 answers:

Mrac [35] · Answer 1 · 2022-04-08T08:33:04+03:00

Mrac [35]3 years ago

7 0

Answer: No. Choosing two dimes are dependent events. The probability of choosing the first dime is 1/4 and the probability of choosing the second dime is 1/7. The probability that both coins are dimes is (1/4)(1/7) = 1/28.

Step-by-step explanation:

scZoUnD [109] · Answer 2 · 2022-04-08T10:28:08+03:00

scZoUnD [109]3 years ago

6 0

Answer:

Step-by-step explanation:

2/8×1/7=1/28