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irina [24]
3 years ago
5

What is -2 + something = 10

Mathematics
2 answers:
netineya [11]3 years ago
7 0
12 because negative two taken away from positive 12 equals positive 10
rosijanka [135]3 years ago
4 0

Answer:

12.

Step-by-step explanation:

It is simple. If you look at the answer and think "If I'm at -2 on a number line, how many am I going to count to get to 10? Try looking up a number line or making one. You can also take the answer plus the -2 that you have to equal 12. Hope this helps.

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How much does 4 5/7 kg of candy cost if 5/6 kg costs $7.50
Aliun [14]

Answer:

It costs $42.43

Step-by-step explanation:

Lets explain how to solve the problem

- The cost of \frac{5}{6} kilogram of candy is $7.5

- We need to find the cost of 4\frac{5}{7} kilogram

We  can use the ratio to find the answer

======= Dollar   :    Kilogram

======= 7.5        :    \frac{5}{6}

=======  c           :    4\frac{5}{7}  

By using cross multiplication

∴ c × \frac{5}{6} = 7.5 × 4\frac{5}{7}

∵ 4\frac{5}{7} = \frac{4*7+5}{7}

∴ 4\frac{5}{7} = \frac{33}{7}

∴ c × \frac{5}{6} = 7.5 × \frac{33}{7}

∴ c × \frac{5}{6} = \frac{495}{14}

Divide both sides by \frac{5}{6}

∴ c = \frac{495}{14} ÷ \frac{5}{6}

Change the division sign to multiplication sign and reciprocal the

fraction after the division sign

∴ c = \frac{495}{14} × \frac{6}{5}

∴ c = \frac{297}{7} = 42.43 dollars

∵ c represents the cost of 4\frac{5}{7} kg

∴ It costs $42.43

7 0
4 years ago
Twenty boys signed up for the school play. The number of girls who signed up was 195% of the number of boys. At the auditions, o
Firlakuza [10]
20 boys signed up
# of girls who signed up was 195% of the number of boys who signed up

Find 195% of 20:

1.95 * 20 = 39

So 39 girls signed up.

To find out what percent of girls who signed up for the play attended the auditions, divide 26 to the total number of girls who signed up:

26 / 39 = 0.666666667

Multiply by 100:

0.666666667 * 100 = 66.6666667%

So approximately 66.67% or 66 2/3%
7 0
4 years ago
Let p = the product of all the odd integers between 500 and 598, and let q = the product of all the odd integers between 500 and
ANEK [815]

Answer:

\frac{360000q}{359999}

Step-by-step explanation:

p = Product of all odd integers between 500 an 598. So,

p = 501 x 503 x 505 ... x 595 x 597

q = Product of all odd integers between 500 and 602. So,

q = 501 x 503 x 505 ... x 595 x 597 x 599 x 601

From the above relations, we can see that q is equal to p multiplied by 599 and 601. i.e.

q = p x 599 x 601

or,

p=\frac{q}{599 \times 601}

We need to evaluate 1p + 1q in terms of q. Using the value of p from above expression, we get:

p+q=\frac{q}{599 \times 601} + q\\\\ p+q=\frac{q+(599 \times 601q)}{599 \times 601}\\ \\ p+q=\frac{q(1+599\times601)}{599 \times 601}\\\\ p+q=\frac{360000q}{359999}

7 0
3 years ago
Ten years from now, a will be twice as old as
WINSTONCH [101]
A present age for a is idk srry dude 
6 0
3 years ago
The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = (x – 10). What is the stan
ra1l [238]
2x-5y=-17!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
3 0
4 years ago
Read 2 more answers
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