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Nady [450]
3 years ago
5

VVVVVVVVVVVVVVVVVVVVVVVVVV

Mathematics
2 answers:
ki77a [65]3 years ago
7 0
X=15 is your answer. Give brainliest if possible.
Step2247 [10]3 years ago
6 0
X=15, 7×3=21, 5×3=15
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8 0
2 years ago
• Which of the following equations represents a line that is perpendicular to
JulsSmile [24]

Answer:

C

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 4x + 9 ← is in slope- intercept form

with slope m = - 4

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{-4} = \frac{1}{4}, hence

y = \frac{1}{4} x + c ← is the partial equation of the perpendicular line

To find c substitute (4, 5) into the partial equation

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y = \frac{1}{4} x + 4 ← equation of perpendicular line → C

4 0
3 years ago
I was on vacation for a month, and now I'm really behind in math. Can anyone help? Thanks~
koban [17]
X+6 = 3x - 12 (right?)
6 = 2x-12
18 = 2x
9 = x


4x-15 = 2x+3
2x-15 = 3
2x = 18
x = 9

Basically, x = 9
7 0
3 years ago
Jane wants to find the area of a trapezoid. To find the area of a trapezoid, add the two bases, multiply by the height, then div
yawa3891 [41]
You do not show us, so I can not answer this question.
8 0
3 years ago
Find the zeros of the function and state their multiplicities. y=x^4-8x^2+16
Volgvan
   
y=0\\\\ 
x^4-8x^2+16 = 0\\\\
(x^2)^2 - 2\cdot 4 \cdot x^2 + 4^2 = 0\\\\
(x^2 - 4)^2 = 0\\\\
(x^2 - 4)(x^2 - 4)=0\\\\
(x-2)(x+2) (x-2)(x+2) = 0\\\\
(x-2)(x-2) (x+2)(x+2) = 0\\\\
\Longrightarrow~~~ x_1 = 2;~x_2 = 2;~ x_3= -2;~x_4 = -2\\\\
\text{Conclusion:}\\\\
x_1 = x_2 = 2~~~   \text{double root}\\\\
x_3 = x_4 = -2~~~   \text{double root}\\\\




7 0
3 years ago
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