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3 years ago

The ratio of a human's femur (thigh bone)

Mathematics

1 answer:

Deffense [45]3 years ago

6 0

Answer:

1.45 feet

Explanation:

5.8/4 = 1.45

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How do I calculate this? Is there a formula?

alex41 [277]

Answer:

Height of cables = 23.75 meters

Step-by-step explanation:

We are given that the road is suspended from twin towers whose cables are parabolic in shape.

For this situation, imagine a graph where the x-axis represent the road surface and the point (0,0) represents the point that is on the road surface midway between the two towers.

Then draw a parabola having vertex at (0,0) and curving upwards on either side of the vertex at a distance of $x = 600$ or $x = -600$ , and y at 95.

We know that the equation of a parabola is in the form $y=ax^2$ and here it passes through the point $(600, 95)$ .

$y=ax^2$

$95=a \times 600^2$

$a=\frac{95}{360000}$

$a=\frac{19}{72000}$

So new equation for parabola would be $y=\frac{19x^2}{72000}$ .

Now we have to find the height $(y)$ of the cable when $x= 300$ .

$y=\frac{19 (300)^2}{72000}$

y = 23.75 meters

8 0

3 years ago

Read 2 more answers

Consider the given function of an arithmetic sequence. f(n) = -5n + 8

Goshia [24]

Answer:

f(9) = -37

Step-by-step explanation:

f(n) = -5n + 8

f(9) = -5(9) + 8

f(9) = -45 + 8

f(9) = -37

8 0

3 years ago

In the figure, PQ is parallel to RS. The length of RP is 5cm; the length of PT is 30cm; the length of QT is 60cm. What is the le

rjkz [21]

The triangles PTQ and RTS are similar; so the ratios of corresponding sides are equal.

Let us denote the unknown length SQ as x.

We could make the following similarity relation;

$\begin{gathered} \frac{30}{30+5}=\frac{60}{60+x} \\ \end{gathered}$

Cross multiply to obtain;

$\begin{gathered} 30(60+x)=60(35) \\ 1800+30x=2100 \\ \text{collect like terms} \\ 30x=2100-1800 \\ 30x=300 \\ \text{divide both sides by 30} \\ \frac{30x}{30}=\frac{300}{30} \end{gathered}$

Therefore;