Answer:
A. The bobsled acceleration is 3.14 m/s²
Explanation:
Given:
Mass of the bobsled (m) = 132 kg
Force of push (F) = 450.0 N
Force of friction (f) = 35 N
Let the acceleration of the bobsled be 'a' m/s².
Now, as per Newton's second law, the net force acting on a body is equal to the product of mass and acceleration.
Net force acting on the bobsled is equal to the difference of applied force and friction and is given as:
![F_{net}=F-f\\\\F_{net}=450.0\ N-35\ N=415\ N](https://tex.z-dn.net/?f=F_%7Bnet%7D%3DF-f%5C%5C%5C%5CF_%7Bnet%7D%3D450.0%5C%20N-35%5C%20N%3D415%5C%20N)
Now, from Newton's second law,
![F_{net}=ma\\\\a=\dfrac{F_{net}}{m}](https://tex.z-dn.net/?f=F_%7Bnet%7D%3Dma%5C%5C%5C%5Ca%3D%5Cdfrac%7BF_%7Bnet%7D%7D%7Bm%7D)
Plug in all the values given and solve for 'a'. This gives,
![a=\frac{415\ N}{132\ kg}\\\\a=3.14\ m/s^2](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B415%5C%20N%7D%7B132%5C%20kg%7D%5C%5C%5C%5Ca%3D3.14%5C%20m%2Fs%5E2)
Therefore, the acceleration is 3.14 m/s². So, option (A) is correct.