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9966 [12]
3 years ago
8

How are ice liquid water and water vapor different from each other?

Physics
2 answers:
olga_2 [115]3 years ago
7 0
The molecules of ice stick together in the process of cohesion. They are tightly packed so there isn't much room to move. Liquid water is a looser hold. The molecules can go past one another, and they will take the shape of whatever container they occupy. Water vapor is loosely contained, and it will will fill whatever container it is kept in, and it will take its shape, too.
Montano1993 [528]3 years ago
3 0
Ice is a solid water is a liquid and water vapor is a gas the 3 states of matter
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A certain atom has only three energy levels. From lowest to highest energy, these levels are denoted n = 1, n = 2, and n = 3. Wh
shtirl [24]

Answer:

D. 160 nm

Explanation:

The energy released from n = 3 to n = 1 must be equal to the sum of energies released from n = 3 to n = 2 and from n = 2 to n = 1. Therefore,

Energy of Photon from 3 to 1 = Energy of Photon from 3 to 2 + Energy of Photon from 2 to 1

\frac{hc}{\lambda} = \frac{hc}{\lambda_{1}} + \frac{hc}{\lambda_{2}}\\\\\frac{1}{\lambda} = \frac{1}{\lambda_{1}} + \frac{1}{\lambda_{2}}

where,

λ = wavelength of photon released from 3 to 1 = ?

λ₁ = wavelength of photon released from 3 to 2 = 800 nm

λ₂ = wavelength of photon released from 2 to 1 = 200 nm

Therefore,

\frac{1}{\lambda} = \frac{1}{800\ nm} + \frac{1}{200\ nm}\\\\\frac{1}{\lambda} = 0.00625 nm^{-1}\\\\\lambda = \frac{1}{0.00625 nm^{-1}}\\\\\lambda = 160 nm

Therefore, the correct option is:

<u>D. 160 nm</u>

5 0
3 years ago
A 40 kg dog is sitting on top of a hillside and has a potential energy of 1,568 J. What is the height of the hillside?
beks73 [17]
Potential Energy=M x G x  H
1,568=40 x 10 x H 
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8 0
3 years ago
BRAINLIEST!!!PLEASE HELP
olasank [31]
I believe its A
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By inductive and deductive reseachhhhh
5 0
3 years ago
What is coldest planet in solar system?
Helga [31]
Im pretty sure its neptune. Its mot pluto because its not a planet. Good luck.
7 0
3 years ago
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A 29.0-kg child on a 3.00-m-long swing is released from rest when the ropes of the swing make an angle of 25.0° with the vertica
KiRa [710]

Answer:

v = 2.348 m/s

Explanation:

Let:

h be the height of the child above the swing's low point,

v be the speed at the low point.

When the ropes make angle 3

25 deg. with the vertical:

h = 3.00(1 - cos(25)).

Equating potential energy at the high point to kinetic energy at the low point:

29.0 * 9.81 * 3.00(1 - cos(25)) = 29.0v^2 / 2

79.96 =29.0v^2 / 2

v = 2.348 m/s

6 0
3 years ago
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