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Lyrx [107]
3 years ago
15

Question 10 (2 points)

Physics
1 answer:
Stella [2.4K]3 years ago
8 0

Answer:

gamma rays

Explanation:

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An unstrained horizontal spring has a length of 0.31 m and a spring constant of 220 N/m. Two small charged objects are attached
Kruka [31]
The solution you should use is Hooke's law: F=-kx

It should have the same signs because they repel due to the stretch of the spring. 

a. Since there is a constant energy within the spring, then Hooke's law will determine the possible algebraic signs. The solution should be 
<span>F = kx 
270 N/m x 0.38 m = 102.6 N 
</span>
b. Then use Coulomb's law; F=kq1q2/r^2 to find the charges produced in the force. 



8 0
3 years ago
Calculate the kinetic energy in joules of a 1500 kg automobile moving at 19 m/s
Svetlanka [38]
Using
KE = ½mv² = ½×1500×19×19 = 270750 joules
5 0
3 years ago
The length of a simple pendulum is 0.760 m, the pendulum bob has a mass of 365 grams, and it is released at an angle of 12.0o to
Allushta [10]

Answer:

0.572 Hz

Explanation:

given,

length of simple pendulum, l = 0.76 m

mass of the bob, m = 365 g = 0.365 Kg

angle made from the vertical, = 12°

frequency, f = ?

f = \dfrac{1}{2\pi}\sqrt{\dfrac{g}{L}}

f = \dfrac{1}{2\pi}\sqrt{\dfrac{9.8}{0.76}}

f = \dfrac{1}{2\pi}\times 3.59

       f = 0.572 Hz

The frequency at which pendulum vibrates is equal to 0.572 Hz

3 0
3 years ago
A truck slows from a velocity of 25 m/s to a stop in 70 m. What was the truck’s acceleration
igomit [66]

v^2-u^2=2 x a x d

25^2-0^2=2 x a x 70

625-0=140 x a

625=140a

a=625/140

a=4.46 m/s^2

im not very sure but i think this is how you do this

4 0
2 years ago
Parasaurolophus was a dinosaur whose distinguishing feature was a hollow crest on the head. The 1.3 m long hollow tube in the cr
yarga [219]

Answer:

67.31 Hz, 201.92 Hz, 336.54 Hz

Explanation:

Resonance also known as standing wave occur when a uniform tube is closed at one end and open at the other end.  

For a resonance wave in a tube with length b, wavelength λ of resonance wave is 4b because a quarter wave is formed in the tube, that is,  

           λ = 4b.  

When the speed of sound is c, the frequency of sound, f, is  

           f = c /λ,  

and therefore,  

           f = c / ( 4b ).  

From the question,

When c = 350 m/s and b = 1.3 m,  

using the formula            

fn = c / ( 4b ) × n (n = 1, 3, 5, ...).  

The first three resonant frequencies are;

First resonance frequency is

f = 350 / (4*1.3) * 1 = 67.31 Hz

Second resonance frequency is

f = 350 / (4*1.3) * 3 = 201.92 Hz

Third resonance frequency is

f = 350 / (4*1.3) * 5 = 336.54 Hz

5 0
3 years ago
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