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lana66690 [7]
3 years ago
7

What mass of octane must be burned in order to liberate 5270 kj of heat? δhcomb = -5471 kj/mol?

Chemistry
1 answer:
katrin2010 [14]3 years ago
6 0
As,
                           5471 kJ heat is given by  =  1 mole of Octane
Then,
                    5310 kJ heat will be given by  = X moles of Octane

Solving for X,
                                  X  =  (5310 kJ × 1 mol) ÷ 5471 kJ

                                  X  =  0.970 moles of Ocatne

So, 0.970 moles of Octane will liberate 5310 kJ energy. Now changing moles to mass,
As,
                                  Moles  =  mass / M.mass
Or,
                                  Mass  =  Moles × M.mass
Putting values,
                                  Mass  =  0.970 mol × 114.23 g/mol

                                  Mass  =  110.83 g of Octane
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Determine the moles of NH3 that can form from 70.0 grams N2.
Darina [25.2K]

Hey there!

5 moles will be produced.

N₂ has a molar mass of 28.014 g/mol.

Convert 70g to mol:

70 ÷ 28.014 = 2.5

In N₂ there are 2 nitrogen atoms. In NH₃ there is 1 nitrogen atom.

So, there will be twice as many moles of NH₃ because every one molecule of N₂ will produce two molecules of NH₃.

2.5 x 2 = 5 moles

Hope this helps!

4 0
3 years ago
How many moles are in 272 grams of hydrogen peroxide (H2O2) ?
Strike441 [17]

Answer:

8 moles

Explanation:

When we are asked to convert from grams of a substance into moles, we have to use the substance's molar mass.

Meaning that for this problem, we'll <em>use the molar mass of hydrogen peroxide</em> (H₂O₂), as follows:

  • 272 g ÷ 34 g/mol = 8 mol

There are 8 moles in 272 grams of hydrogen peroxide.

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2 years ago
According to Table I, which salt releases energy as it dissolves?
CaHeK987 [17]
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3 0
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The molecule NH3 contains all single bonds.<br><br> true <br> false
dsp73
<h3><u>Answer;</u></h3>

True

<h3><u>Explanation</u>;</h3>
  • The molecule NH3 contains all single bonds.
  • NH3 has a three single covalent  bond among its nitrogen and hydrogen atoms,because one valence electron of each of three atom of hydrogen is shared with three electron.
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8 0
3 years ago
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Calculate the new volume of 1.23 mL of a gas at 32 C is subjected to drop in temperature of 20 degrees Celsius
kotykmax [81]

Answer:

1,15mL = V₂

Explanation:

Based on Charle's law the volume is directely proportional to the absolute temperature in a gas under constant pressure. The equation is:

V₁T₂ = V₂T₁

<em>Where V is volume and T absolute temperature of a gas where 1 is initial state and 2, final state.</em>

The V₁ is 1.23mL

T₁ = 32°C + 273.15 = 305.15K

T₂ = T₁ - 20°C = 285.15K

Replacing:

1.23mL*285.15K = V₂*305.15K

<h3>1,15mL = V₂</h3>

<em />

8 0
2 years ago
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