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Norma-Jean [14]
3 years ago
11

A plastic 2L soda bottle is flexible enough that the volume of the bottle can change even without opening it. If you have an emp

ty soda bottle (volume of 2.0L) at room temperature (25°), what will the new volume be if you put it in your freezer (-4.0°C)?
Chemistry
1 answer:
Aneli [31]3 years ago
8 0

Answer:  The new volume be if you put it in your freezer is 1.8 L

Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=2L\\T_1=25^oC=(25+273)K=298K\\V_2=?\\T_2=-4.0^oC=((-4)+273)K=269K

Putting values in above equation, we get:

\frac{2}{298}=\frac{V_2}{269}\\\\V_2=1.8L

The new volume be if you put it in your freezer is 1.8 L

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When 8.00x10^22 molecules of ammonia react with 7.00x10^22 molecules of oxygen according to the chemical equation shown below, h
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4NH₃                   <span>+                        3O</span>₂                      ⇒<span>          2N</span>₂<span> + 6H</span>₂<span>O
</span>4mol                     :                        3mol                   :             2mol
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limiting reactant

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If i have 8 L of 0.25 M solution, how many miles of MgCl2 are present
qaws [65]

Answer:

2 moles

Explanation:

The following were obtained from the question:

Molarity = 0.25 M

Volume = 8L

Mole =?

Molarity is simply defined as the mole of solute per unit litre of solution. It is represented mathematically as:

Molarity = mole of solute/Volume of solution.

With the above equation, we can easily find the number of mole of MgCl2 present in 8 L of 0.25 M MgCl2 solution as follow:

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Therefore, 2 moles of MgCl2 are present in 8 L of 0.25 M MgCl2 solution

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