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Norma-Jean [14]
3 years ago
11

A plastic 2L soda bottle is flexible enough that the volume of the bottle can change even without opening it. If you have an emp

ty soda bottle (volume of 2.0L) at room temperature (25°), what will the new volume be if you put it in your freezer (-4.0°C)?
Chemistry
1 answer:
Aneli [31]3 years ago
8 0

Answer:  The new volume be if you put it in your freezer is 1.8 L

Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=2L\\T_1=25^oC=(25+273)K=298K\\V_2=?\\T_2=-4.0^oC=((-4)+273)K=269K

Putting values in above equation, we get:

\frac{2}{298}=\frac{V_2}{269}\\\\V_2=1.8L

The new volume be if you put it in your freezer is 1.8 L

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➡ ANSWER

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3 years ago
Its minerals will have crystals.
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3 0
3 years ago
A 25.0g tin sample was placed in boiling water at 99.5 C until it had the same temperature. Afterwards, the tin sample was place
MrMuchimi

Answer : The specific heat of tin is, 0.213 J/g.K

Explanation :

Formula used :

q=m\times c\times (T_{final}-T_{initial})

where,

q = amount of heat lost = -399.4 J

c = specific heat capacity of tin = ?

m = mass of tin = 25.0 g

T_{final} = final temperature = 24.5^oC=273+24.5=297.5K

T_{initial} = initial temperature = 99.5^oC=273+99.5=372.5K

Now put all the given values in the above formula, we get:

-399.4J=25.0g\times c\times (297.5-372.5)K

c=0.213J/g.K

Therefore, the specific heat of tin is, 0.213 J/g.K

7 0
3 years ago
If you have 1.00 mole of F2 at 1.00 atm of pressure and 0°C, what is the volume of F2?
ss7ja [257]

Answer:

V=22.4L

Explanation:

Hello,

In this case, by using the ideal gas equation, er can compute the volume of fluorine gas as shown below:

PV=nRT\\\\V=\frac{nRT}{P}=\frac{1mol*0.082\frac{atm*L}{mol*K}+(0+273)K}{1.00atm}  \\\\V=22.4L

Best regards.

4 0
3 years ago
How many grams of Li are there in 1.39 moles of Li?
Ulleksa [173]

Answer:

6.941 grams

Explanation:

The molecular formula for Lithium is Li. The Si base unit for amount of substance is mole. 1 mole is equal to 1 moles Lithium, or 6.941 grams

5 0
3 years ago
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