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larisa86 [58]
3 years ago
14

Steel is an alloy of one or more elements combined with which metal?

Chemistry
1 answer:
vlabodo [156]3 years ago
4 0

The answer is iron.  Hope it helps!

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Which soil layer contains the most humus?<br> A) A horizon B) B horizon C) C horizon D) D horizon
Bad White [126]
None. It's the O horizon. Compromises of mostly decomposed plant litter.
5 0
3 years ago
Question 1 of 10
Butoxors [25]

Answer:

C for sure.

Explanation:

4 0
3 years ago
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Carbon disulfide burns in oxygen to yield car- bon dioxide and sulfur dioxide according to the chemical equation cs2(l) 3 o2(g)
vampirchik [111]

Answer: Oxygen is the limiting reagent.

Explanation: CS_2(l)+3O_2(g)\rightarrow CO_2(g)+2SO_2(g)

As can be seen from the given balanced equation:

3 moles of O_2 reacts with 1 mole of CS_2

1.52 moles of O_2 reacts with=\frac{1}{3}\times 1.52=0.51moles of CS_2

Thus O_2 is the limiting reagent as it limits the formation of products. (0.91-0.51)= 0.40 moles of CS_2 will remain as such and thus  CS_2 is an excess reagent.

6 0
3 years ago
Gallium arsenide, GaAs, has gained widespread use in semiconductor devices that convert light and electrical signals in fiber-op
stira [4]

Answer:

Five peaks  

Explanation:

GaAs would show two peaks:

Ga-69 + As-75 = 144

Ga-71 + As-75 = 146

Their intensities are in the ratio 60 : 40 = 100:67.

Ga₂S₂ would show three peaks:

Ga-69 + Ga-69 + 2As-75 = (Ga-69)₂(As-75)₂ = 288

Ga-69 + Ga-71 + 2As-75 = (Ga-69)(Ga-71(As-75)₂ = 290

Ga-71 + Ga-71 + 2As-75 = (Ga-71)₂(As-75)₂ = 292

Their relative intensities are in the ratio

(60 + 40)² = 60² : 2×60×40 : 40² = 3600 : 4800 : 1600 = 75 : 100 : 33

A spectrum of a mixture of GaAs and Ga₂As₂ would show five peaks:

Two at m/e 144 and 146 with intensity ratios 100: 67 and

Three at m/e 288, 290, and 292 with intensity ratios 75:100 :33.

We cannot predict the absolute sizes of the peaks because we do not know the relative amounts of GaAs and GaAs₂.

6 0
4 years ago
What is the concentration of OH− and pOH in a 0.00072 M solution of Ba(OH)2 at 25 ∘C? Assume complete dissociation.
Mumz [18]

Given :

0.00072 M solution of Ba(OH)_2 at 25^oC .

To Find :

The concentration of OH^-and pOH .

Solution :

1 mole of Ba(OH)_2 gives 2 moles of OH^- ions .

So , 0.00072 M mole of Ba(OH)_2 gives :

[OH^-]=2 \times 0.00072\ M

[OH^-]=0.00144\ M

[OH^-]=1.44\times 10^{-3}\ M

Now , pOH is given by :

pOH=-log[OH^-]\\\\pOH=-log[1.44\times 10^{-3}]\\\\pOH=2.84

Hence , this is the required solution .

3 0
3 years ago
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