The answer is covalent bond!
Answer:
Lithium Fluoride.
Explanation:I know science.
Molarity = number of moles/Volume (L). Solve for the number of moles in the initial solution (3.78M = n/0.3 L) and then use that amount of moles and the new volume (0.5 L) to solve for the new Molarity.
Answer:
Explanation:
2 H₂S(g) +S0₂(g) = 3 S(s) + 2H₂0(g)
2 x 34 g 64 g 3 x 32 g
68 g of H₂S reacts with 64 g of S0₂
3.89 g of H₂S reacts with 64 x 3 .89 / 68 g of S0₂
3.89 g of H₂S reacts with 3.66 g of S0₂
S0₂ given is 4.11 g , so it is in excess .
Hence H₂S is limiting reagent .
68 g of H₂S reacts with S0₂ to give 96 g of Sulphur
3.89 g of H₂S reacts with S0₂ to give 96 x 3.89 / 68 g of Sulphur
3.89 g of H₂S reacts with S0₂ to give 96 x 3.89 / 68 g of Sulphur
5.49 g of Sulphur is produced .
Actual yield is 4.89
percentage yield = 4.89 x 100 / 5.49
= 89 % .
<span>The following is the order from lowest boiling point to highest based on the types of forces these compounds have:
CO2
CH3Br
CH3OH
RbF
CO2 is a nonpolar molecular compound. The only intermolecular force present is a relatively weak dispersion force, because of the small molar mass. CO2 will have the lowest boiling point. ď‚· CH3Br is a polar molecule. Dispersion forces (present in all matter) and dipoleâ’dipole forces will be present. This compound has the next highest boiling point. ď‚· CH3OH is a polar molecule, which can form hydrogen bonds; these are especially strong dipole-dipole attractions. Dispersion forces and hydrogen bonding are present to give this substance the next highest boiling point. ď‚· RbF is an ionic compound. Ionâ’ion attractions are much stronger than any intermolecular force. RbF has the highest boiling point</span>