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larisa86 [58]
3 years ago
14

Steel is an alloy of one or more elements combined with which metal?

Chemistry
1 answer:
vlabodo [156]3 years ago
4 0

The answer is iron.  Hope it helps!

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Group 18 noble gases are relatively inert because *
choli [55]

Answer:I believe its A. There noble gasses so there happy with there electron count!

Explanation:

3 0
3 years ago
Which statement is true about activision energy
puteri [66]

Answer:

can you provide more to the question

Explanation:

6 0
3 years ago
A gas mixture contains ar and h2. what is the total pressure of the mixture, if the mole fraction of h2 is 0. 350 atm and the pr
nasty-shy [4]

Considering the Dalton's partial pressure, the total pressure in the mixture of gases is 1.371 atm.

The pressure exerted by a particular gas in a mixture is known as its partial pressure.

So, Dalton's law states that the total pressure of a gas mixture is equal to the sum of the pressures that each gas would exert if it were alone:

P_{T} = P_{1}+P_{2}+......+P_{n}

where n is the amount of gases in the mixture.

Dalton's partial pressure law can also be expressed in terms of the mole fraction of the gas in the mixture.  So in a mixture of two or more gases, the partial pressure of gas A can be expressed as:

P_{A} = X_{a}P_{T}

In this case, the partial pressure of gas H₂ can be expressed as:

P_{H2} = X_{H2} P_{T}

You know:

P_{H2} = 0.48 atm

X_{H2} = 0.35

Replacing in the definition of partial pressure of gas H₂:

0.48atm = 0.35P_{T}

Solving:

P_{T} = \frac{0.48atm}{0.35}

P_{T}= 1.371 atm

In summary, the total pressure in the mixture of gases is 1.371 atm.

Learn more about partial pressure: brainly.com/question/15302032

#SPJ4

5 0
1 year ago
If a laser light is compose of photons each with an energy of 4.58 × 10−19 J, what is the photon energy of this light in units o
kap26 [50]

Answer : The photon energy of this light in units of nanometers, (nm) is, 4.34\times 10^{-2}nm

Solution :

Formula used :

E=\frac{h\times c}{\lambda}

where,

E = energy of photon = 4.58\times 10^{-19}J

h = Planck's constant = 6.626\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda = wavelength = ?

Now put all the given values in the above formula, we get:

4.58\times 10^{-19}J=\frac{(6.626\times 10^{-34}Js)\times (3\times 10^8m/s)}{\lambda}

\lambda=4.3017\times 10^{-7}m=434.017\times 10^{-9}m=434.017nm=4.34\times 10^{-2}nm

conversion used : (1nm=1\times 10^{-9}m)

Therefore, the photon energy of this light in units of nanometers, (nm) is, 4.34\times 10^{-2}nm

5 0
3 years ago
Electrons will readily tunnel out of the surface of a metal when a sufficiently high electric field E is applied to the surface.
puteri [66]

Answer:

1 that is 100%

Explanation:

here it is given that Fermi energy of the of the metal = 5 e.V

work function= 4 e.V

we have to find the probability that an incident electron will tunnel out if E=109 V/m

WORK FUNCTION : work function is defined as the energy required to withdraw an electron completely from the metal surface.

now the energy per unit volume in electric field is given by

E= \frac{1}{2}\times \varepsilon_0\times E^{2}

E=\frac{1}{2}\times 8.854\times 10^{-12}\times \left ( 10^{9} \right )^2

E=4.427\times 10^{6}joule

in electron volt E=4.427\times 10^{6}joule × 6.24\times 10^{18}

E=2.76\times 10^{25}e.V

hence the applied energy per unit volume is greater than the work work function of electron so there is probability of 100% that electron will tunnel out

3 0
3 years ago
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