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andrew11 [14]
3 years ago
13

Round 90608.5881594 to 1 decimal place

Mathematics
2 answers:
zalisa [80]3 years ago
8 0
90608.6 is the answer

<span> Remember if the number after this line is less than 5 </span>round<span> down, or </span>round<span> up if the number is 5 or above.</span>
Leno4ka [110]3 years ago
7 0

Answer:

90608.6

Step-by-step explanation:

Round 90608.5881594 to 1 decimal place

To round the answer to 1 decimal place , we round the answer to nearest tenth.

In the given number , 5 after decimal point is in tenths place

8 is in hundredths place

Here 8 in hundredths place is greater than 5. If it is greater than 5 then we add 1 in tenths place

So 5 in tenths place becomes 6

90608.5881594 to 1 decimal place is 90608.6

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Step-by-step explanation:

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A ship leaves port at noon and has a bearing of S29oW. The ship sails at 20 knots. How many nautical miles south and how many na
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Answer:

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Step-by-step explanation:

Let v denote the speed of the ship, and let t denote the duration of the trip. The magnitude of the displacement of this ship would be v\, t.

Refer to the diagram attached. The direction {\rm S$29^{\circ}$W} means 29^{\circ} west of south. Thus, start with the south direction and turn towards west (clockwise) by 29^{\circ} to find the direction of the displacement of the ship.

The hypothenuse of the right triangle in this diagram represents the displacement of the ship, with a length of v\, t. The dashed horizontal line segment represents the distance that the ship has travelled to the west (which this question is asking for.) The angle opposite to that line segment is exactly 29^{\circ}.

Since the hypotenuse is of length v\, t, the dashed line segment opposite to the \theta = 29^{\circ} vertex would have a length of:

\begin{aligned}& \text{opposite (to $\theta$)} \\ =\; & \text{hypotenuse} \times \frac{\text{opposite (to $\theta$)}}{\text{hypotenuse}} \\ =\; & \text{hypotenuse} \times \sin (\theta) \\ =\; & v\, t \, \sin(\theta) \\ =\; & v\, t\, \sin(29^{\circ})\end{aligned}.

Substitute in \begin{aligned} v &= 20\; \frac{\text{nautical mile}}{\text{hour}}\end{aligned} and t = 6\; \text{hour}:

\begin{aligned} & v\, t\, \sin(29^{\circ}) \\ =\; & 20\; \frac{\text{nautical mile}}{\text{hour}} \times 6\; \text{hour} \times \sin(29^{\circ}) \\ \approx\; & 58.2\; \text{nautical mile}\end{aligned}.

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Step-by-step explanation:

This clarifies it https://artofproblemsolving.com/wiki/index.php/2020_AMC_8_Problems/Problem_23

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