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jok3333 [9.3K]
3 years ago
14

Answer Choices:

Mathematics
1 answer:
tatiyna3 years ago
5 0

Answer:

positive infinity bc it is going up

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perimetrul unui paralelogram este de 30 cm.una dintre laturi are lungimea de 6 metri . dterminati lungimile celolrarte laturi
zzz [600]

To solve this problem you must apply the proccedure shown below:

1. By definition, the opposite sides of a parallelogram are parallel and have equal length.

2. The figure attached shows that the opposite sides with equal length are:

a=c\\b=d

3. Keeping this on mind, you have that the side <em>c</em> and <em>a</em> are equal and measure six centimeters.

4. To find the length of the other sides, you must apply the following formula for calculate the perimeter of a parallelogram:

P=2(a+b)

4. If you solve for <em>b</em>, you will obtain the measure of <em>b </em>and<em> d:</em>

30cm=2(6cm+b)\\30cm=12cm+2b\\b=9cm

Therefore the answer is:

 The lengths of the sides are: 6 cm, 6 cm, 9 cm and 9 cm.

8 0
2 years ago
-2 (z + 11) = 6<br><br> Please help. You have to use distributive property.
Mamont248 [21]

Answer:

-14

Step-by-step explanation:

-2(z+11)=6

-2z-22=6

-2z=28

z=-14

4 0
2 years ago
HELPPPPPP PLEASEEEE HELP HELP
Delvig [45]

Answer:

i believe the answer is 3pi/4

5 0
3 years ago
An angle of 200 is a/an _______ angle.<br> a. reflex<br> b. straight<br> c. right<br> d. acute
krok68 [10]
Reflex angle because straight is 180 and right is 90 and acute is less than 90
3 0
2 years ago
Is 2.0 a solution to the equation?<br><br> X-2y=0 , 2x-3y=1
Travka [436]
No, because (2,0) is a coordinate. x=2 and y=0. So just plug in the numbers where there's x or y with the appropriate number, (2 or 0). So in the first equation, x-2y=0, when you pug in the numbers, 2-2(0)=0, you know it's wrong because 2-0=0 isn't correct. So no. the point (2,0) is not a solution to the first equation. Now plug in the numbers for the second coordinate. You get 2(2)-3(0)=1. So 4-0=1. This is once again false no no. (2,0) satisfies neither equations. 
8 0
2 years ago
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