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kirza4 [7]
3 years ago
10

A 5.50 kg crate is suspended from the end of a short vertical rope of negligible mass. An upward force F(t) is applied to the en

d of the rope, and the height of the crate above its initial position is given by y(t) =(2.80 m/s)t +(0.61 m/s^3)t^3.
Required:
a. What is the magnitude of the force F when 4.10s ?
b. Is the magnitude's unit N but the system doesn't accept it?
Physics
1 answer:
11Alexandr11 [23.1K]3 years ago
8 0

Answer:

Explanation:

position

y(t) = 2.80t + 0.61t³

velocity is the derivative of position

v(t) = 2.80 + 1.83t²

acceleration is the derivative of velocity

a(t) = 3.66t

F = ma = 5.50(3.66(4.10)) = 82.533 N

which should be rounded to no more than three significant digits and arguably only two due to the 0.61 factor.

F = 82.5 N or 83 N

Yes the units are Newtons, cannot tell what your system will accept. May not want the units at all.

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It is the final seconds of an ice hockey game between the Flyers and the Bruins. The Bruins are down by 1 point. With 20 s left
liberstina [14]

Answer:

a

P =0.1094 \ m past the goal post

Yes the Flyers won the match

Explanation:

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Generally the position of the puck when the game clock reaches zero is mathematically represented as

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A car accelerates at a rate of 4.00 m/swest for 5.0 seconds. What is the car's change in
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To know more about uniform magnetic field refer to brainly.com/question/25655915

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