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IrinaVladis [17]
3 years ago
12

In the following reaction, which species is reduced? 2k+br2 yield 2k+ + 2br-

Chemistry
1 answer:
professor190 [17]3 years ago
6 0
The species that is reduced in

2K + Br2 = 2K^+ + 2Br^-


is  Br2 is reduced

This is because  Br2   move from oxidation state  zero  to   oxidation state of negative  one.  K  is  been oxidized since it   move from oxidation  state  zero  to oxidation state  of  positive  one.  K  act as a reducing agent while Br2 act as  a oxidizing  agent
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hope this helps!
4 0
3 years ago
The valences of metal x,y and z are 1,2 and 3 respectively. What are the formulae of their;a) hydroxides, b) sulphates, c) hydro
Rina8888 [55]

Answer:

See answer below

Explanation:

AS we know that the valence for those metals X, Y, and Z are 1, 2 and 3, we can determine the formula of each compound.

1. Hydroxides.

An hydroxide is formed when an oxyde of a metal reacts with water. When this happens, the general molecular formula is:

Meₐ(OH)ₙ

Where:

a: valence or charge of the hydroxide (Which is -1)

n: valence of the metal.

Following this, the formula for X, Y and Z would be:

XOH

Y(OH)₂

Z(OH)₃

2. Sulphates

Sulphates follow a similar rule of hydroxide in the general molecular formula, but instead of having a charge of -1, it has a charge of -2 so:

Mₐ(SO₄)ₙ

So, following the rule:

X₂SO₄

Y₂(SO₄)₂ ------> YSO₄

Z₂(SO₄)₃

3. Hydrogens

Following the same rule as the previous, hydrogens works with a charge of -1, so:

MₐHₙ

Then:

XH

YH₂

ZH₃

4. Carbonates.

This follows the same rule as sulphates, with the same charge so:

Mₐ(CO₃)ₙ

Then:

X₂CO₃

YCO₃

Z₂(CO₃)₃

5. Nitrates

Follow the same rule as the hydroxides, with the same charge of -1.

Mₐ(NO₃)ₙ

Then:

XNO₃

Y(NO₃)₂

Z(NO₃)₂

6. Phosphates

In the case of phosphates, these have a charge of -3 so:

Mₐ(PO₄)ₙ

Then:

X₃PO₄

Y₃(PO₄)₂

Z₃(PO₄)₃ ----> ZPO₄

Hope this helps

6 0
3 years ago
What is the identity of the element whose isotopes you have selected
Pachacha [2.7K]

Answer:

Rubidium

Explanation:

Nil

5 0
3 years ago
Using the reaction C12H22O11 + 12 O2 -&gt;12CO2 + 11H2O (e). How many grams of carbon dioxide can be produced from 456.7g sucros
klio [65]

Answer:

704.6 g CO2

Explanation:

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g CO2 = 456.7 g sucrose x (1 mol sucrose/MM sucrose) x (12 moles CO2/1 mol sucrose) x (MM CO2/1mol CO2) = 704.6 g CO2

7 0
3 years ago
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goblinko [34]

Answer:

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8 0
3 years ago
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