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IrinaVladis [17]
3 years ago
12

In the following reaction, which species is reduced? 2k+br2 yield 2k+ + 2br-

Chemistry
1 answer:
professor190 [17]3 years ago
6 0
The species that is reduced in

2K + Br2 = 2K^+ + 2Br^-


is  Br2 is reduced

This is because  Br2   move from oxidation state  zero  to   oxidation state of negative  one.  K  is  been oxidized since it   move from oxidation  state  zero  to oxidation state  of  positive  one.  K  act as a reducing agent while Br2 act as  a oxidizing  agent
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likoan [24]
6.04 x 10^14. See attached work.

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3 years ago
The solubility product for an insoluble salt with the formula M2X3 is written as ________, where s is the molar solubility
masha68 [24]

Answer:

36s^5

Explanation:

We have;

M2X3 (s)------> 2M^3+(aq)  + 3X^2-(aq)

If [M^3+(aq)] = [X^2-(aq)] = s

We then have;

Ksp = (2s)^2 * (3s)^3

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Ksp = 36s^5

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3 0
3 years ago
Ammonium hydrogen sulfide (NH4HS) can
Sergeu [11.5K]

K_c = \frac{[NH_2]^{1}[H_2S]^{1}}{[NH_2HS]^{1}} is the equilibrium constant expression for

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<h3>Definition of equilibrium constant.</h3>

A number that expresses the relationship between the amounts of products and reactants present at equilibrium in a reversible chemical reaction at a given temperature.

Equilibrium constant for the NH₂HS(S)   →   NH₂(g) + H₂S(g) will be:

K_c = \frac{[Product]^{coefficient}}{[Reactantt]^{coefficient}}

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Hence, option A is correct.

Learn more about the equilibrium constant here:

brainly.com/question/10038290

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8 0
2 years ago
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7 0
3 years ago
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