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Sonja [21]
3 years ago
12

What is the identity of the element whose isotopes you have selected

Chemistry
1 answer:
Pachacha [2.7K]3 years ago
5 0

Answer:

Rubidium

Explanation:

Nil

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Answer:

The correct answer would be A.

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G Calculate the mass, in grams, of 225.0 atoms of cadmium, Cd (1 mol of Cd has a mass of 112.41 g).
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svp [43]

Answer:

C. Splitting the atom

Explanation:

splitting the atom involves fission

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3 years ago
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Select all of the items that are true about a sample of water vapor at 101°C as it cools.
Dvinal [7]
<h3><u>Answer;</u></h3>

A) Its temperature will fall continuously until it condensed into a liquid.

<h3><u>Explanation</u>;</h3>
  • <em><u>Steam or water vapor is the gaseous state of liquid water.  When water vapor above a temperature of 100 degrees Celsius is cooled, the temperature falls continuously, and it undergoes condensation at a temperature of 100 degrees Celsius and turns into liquid water.</u></em>
  • The change of state from gaseous to liquid state occurs as a result of latent heat of vaporization that the water vapor carries.
4 0
3 years ago
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Determine the [OH−] of a solution that is 0.115 M in CO32−. For carbonic acid (H2CO3), Ka1=4.3×10−7 and Ka2=5.6×10−11.
lianna [129]

Answer:

[OH⁻] = 4.3 x 10⁻¹¹M in OH⁻ ions.

Explanation:

Assuming the source of the carbonate ion is from a Group IA carbonate salt (e.g.; Na₂CO₃), then 0.115M Na₂CO₃(aq) => 2(0.115)M Na⁺(aq) + 0.115M CO₃²⁻(aq). The 0.115M CO₃²⁻ then reacts with water to give 0.115M carbonic acid; H₂CO₃(aq) in equilibrium with H⁺(aq) and HCO₃⁻(aq) as the 1st ionization step.

Analysis:

            H₂CO₃(aq)     ⇄     H⁺(aq)    +    HCO₃⁻(aq); Ka(1) = 4.3 x 10⁻⁷

C(i)          0.115M                      0                  0

ΔC              -x                        +x                  +x

C(eq)    0.115M - x                   x                    x

            ≅ 0.115M

Ka(1) = [H⁺(aq)][HCO₃⁻(aq)]/[H₂CO₃(aq)] = [(x)(x)/(0.115)]M = [x²/0.115]M

= 4.3 x 10⁻⁷  => x = [H⁺(aq)]₁ = SqrRt(4.3 x 10⁻⁷ · 0.115)M = 2.32 x 10⁻⁴M in H⁺ ions.

In general, it is assumed that all of the hydronium ion comes from the 1st ionization step as adding 10⁻¹¹ to 10⁻⁷ would be an insignificant change in H⁺ ion concentration. Therefore, using 2.32 x 10⁻⁴M in H⁺ ion  concentration, the hydroxide ion concentration is then calculated from

[H⁺][OH⁻] = Kw => [OH⁻] = (1 x 10⁻¹⁴/2.32 x 10⁻⁴)M = 4.3 x 10⁻¹¹M in OH⁻ ions.

________________________________________________________

NOTE: The 2.32 x 10⁻⁴M  value for [H⁺] is reasonable for carbonic acid solution with pH ≅ 3.5 - 4.0.

4 0
3 years ago
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