Answer:
The molality of isoborneol in camphor is 0.53 mol/kg.
Explanation:
Melting point of pure camphor= T =179°C
Melting point of sample = 
= 165°C
Depression in freezing point = 
Depression in freezing point is also given by formula:
= The freezing point depression constant
m = molality of the sample
i = van't Hoff factor
We have: = 40°C kg/mol
i = 1 ( organic compounds)
The molality of isoborneol in camphor is 0.53 mol/kg.
Answer:
A
Explanation:
liquids thake the shape of what holds them so shape is changing and volume is the same
Answer:
the first thing you do is do your experiment then title it. then state the purpose of the experiment. included a summary of the experiment. make a list of the materials you used. present all the steps in order to make the experiment possible. note any changes to the original procedure. this is basically the steps you have to do in order to make your scientific experiment.
Answer:
Explanation:
Hello.
In this case, since the neutralization of the acid requires equal number of moles of both acid and base:
Whereas we can express it in terms of concentrations and volumes:
Thus, we can compute the volume of sodium hydroxide (base) as follows:
Best regards.
