Answer:
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Answer:
= 9.28 g CO₂
Explanation:
First write a balanced equation:
CH₄ + 2O₂ -> 2H₂O + CO₂
Convert the information to moles
7.50g CH₄ = 0.46875 mol CH₄
13.5g O₂ = 0.421875 mol O₂
Theoretical molar ratio CH₄:O₂ -> 1:2
Actual ratio is 0.46875 : 0.421875 ≈ 1:1
If all CH₄ is used up, there would need to be more O₂
So O₂ is the limiting reactant and we use this in our equation
Use molar ratio to find moles of CO₂
0.421875 mol O₂ * 1 mol CO₂/2 mol O₂=0.2109375 mol CO₂
Then convert to grams
0.2109375 mol CO₂ = 9.28114 g CO₂
round to 3 sig figs
= 9.28 g CO₂
The required volume of water is 0.18 liters.
<h3>What is molarity?</h3>
Molarity of any solution is define as the number of moles of solute present in per liter of solution as;
M = n/V
Moles of solute will be calculated as:
n = W/M, where
W = given mass of HCl = 32g
M = molar mass of HCl = 36.4g/mol
n = 32 / 36.4 = 0.88 mole
Given molarity of solution = 4.80M
On putting all values in the above equation, we get
V = (0.88) / (36.4) = 0.18 L
Hence required volume of water is 0.18L.
To know more about volume & concentration, visit the below link:
brainly.com/question/26762947
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I think there is 4 electrons in the outer shell of 14 atomic number. If I'm wrong, know that I'm not very good.
