3 years ago

Coppedis used in wiring because its

Physics

1 answer:

Salsk061 [2.6K]3 years ago

4 0

Answer:

It is used for its high conductivity and being relatively resistant to high temperatures (?!)

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A right triangle has sides measuring 5 and 12 inches. If the two vectors have a magnitude of 5 and 12 and are at right angles to

ollegr [7]

Answer:

$x=13$

Explanation:

From the question we are told that

Magnitude 1 $M_1=5$

Magnitude 1 $M_2=12$

Generally the Pythagoras equation for the magnitudes is mathematically given as

$\sqrt{x^2}=\sqrt{M_1^2 +M_2^2}$

$\sqrt{x^2}=\sqrt{5^2 +12^2}$

$x=13$

Therefore resultant magnitude is

$x=13$

8 0

3 years ago

A ray of monochromatic light ( f = 5.09 × 10^14 Hz) passes from air into Lucite at an angle

harina [27]

Let us consider the air with the index 1 and the lucite with index 2. Using the Snell's Secound Law, we have:

$\frac{sen\O_{2}}{sen\O_{1}} = \frac{n_{2}}{n_{1}} \\ sen\O_{2}= \frac{n_{2}*sen\O_{1}}{n_{1}}$

Entering the unknowns, remembering that the air refrective index is 1 and the lucite refrective index is 1.5, comes:

$sen\O_{2}= \frac{n_{2}*sen\O_{1}}{n_{1}} \\ sen\O_{2}= \frac{1.5* \frac{1}{2} }{1} \\ sen\O_{2}=0.75$

Using the arcsin properties, we get:

$sen\O_{2}=0.75 \\ arcsin(0.75)=\O_{2} \\ \boxed {\O_{2}=48.59^o}$

Obs: Approximate results, and the drawing is attached

If you notice any mistake in my english, let me know, because i am not native.