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3 years ago

7

What are the main differences between the manual, oscillate and pulse functions?

2 answers:

Artyom0805 [142]3 years ago

7 0

What are the main differences between the manual, oscillate and pulse functions? Manuel function can be used when we move it. Oscillate function automatically moves on its own. The pulse function mimics the pulse of a heart rate and can only be used by pushing the button.

gladu [14]3 years ago

4 0

Answer:

Manuel function can be used when we move it. Oscillate function automatically moves on its own. The pulse function mimics the pulse of a heart rate and can only be used by pushing the button.

Explanation:

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Assume that the ammeter in the figure below is removed and the current that flows through the 4.0Ω path, I3, is unknown. Determi

qaws [65]

The circuit is in parallel connection

Equivalent resistance = 1/Req = 1/R1 + 1/R2 + 1/R3

From the information given,

R1 = 5

R2 = 2

R3 = 4

1/Req = 1/5 + 1/2 + 1/4 = (4 + 10 + 5)/20 = 19/20

Req = 20/19 = 1.053 ohms

I = V/R

Given that V = 12,

Current flow through circuit = 12/1.053 = 11.4 A

I1 + I2 + I3 = 11.4

I1 = 12/5 = 2.4 A

I2 = 12/2 = 6 A

I3 = 12/4 = 3A

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1 year ago

A 3.00 kg object is fastened to a light spring, with the intervening cord passing over a pulley. The pulley is frictionless, and

finlep [7]

Answer:

Part a)

k = 588.6 N/m

Part b)

v = 0.7 m/s

Explanation:

As we know that initially block is at rest

now if block is released from rest then it will go down by 10 cm and again comes to rest

so here we have

Part a)

Work done by gravity + work done by spring force = change in kinetic energy

$W_g + W_{spring} = 0 - 0$

$mg(0.10) + \frac{1}{2}k(0^2 - 0.10^2) = 0$

$3(9.81)(0.10) - \frac{1}{2}k(0.10)^2 = 0$

$k = 588.6 N/m$

Part b)

Now when spring is stretch by x = 5 cm then the speed of the block is given as

$mgx' + \frac{1}{2}k(0^2 - x'^2) = \frac{1}{2}mv^2 - 0$

here we have

$x' = 0.05 m$

$3(9.81)(0.05) - \frac{1}{2}(588.6)(0 - 0.05^2) = \frac{1}{2}(3) v^2$

$1.4715 - 0.736 = 1.5 v^2$

$v = 0.7 m/s$

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3 years ago

An incandescent bulb is supplied with

Serga [27]

Answer:

Efficiency = 5%

Explanation:

Given that,

Supplies energy to the bulb = 100 J

Transferred energy by the bulb = 5 J

We need to find the efficiency of the bulb. It can be given by "

$\eta=\dfrac{\text{useful energy out}}{\text{useful energy in}}\times 100\\\\=\dfrac{5}{100}\times 100\\\\=5\%$

So, the efficiency of the bulb is 5%.

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3 years ago

How many neutrons does an element have of its atomic number is 50 and its mass number is 156?

pshichka [43]

Ok so I think you would first subtract

156 - 50 = 106

Since atomic number is based on the number of protons, you should subtract the 50 from 156

106 should be your answer

Hope this helps!

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4 years ago

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vampirchik [111]

I think its a higher frequency

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3 years ago