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-Dominant- [34]
3 years ago
5

What is the age of a sample if there are 6 grams of an element that have not decayed outof an original 24 grams and has a half-l

ife of 8yrs a. 8yrs b. 50yrs c. 29yrs d. 16yrs
Physics
1 answer:
amid [387]3 years ago
8 0

Answer:

d ) 16 years

Explanation:

If n be number of half years passed then

[tex]\frac{m}{m_0} =\sqrt[n]{\frac{1}{2} }[/tex]

m is mass undecayed m₀ is original mass

Here m = 6 g

m₀ =24 g

Putting these values

\frac{6}{24} =\sqrt[n]{\frac{1}{2} }

n = 2 half lives

age = 2 x 8 = 16 years

= 16 years

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Suppose you were bungee jumping from a bridge while blowing a hand-held air horn. How would someone remaining on the bridge hear
Genrish500 [490]

Answer:

The pitch will progressively lower

Explanation:

If i were bungee jumping from  a bridge while blowing a hand-held air horn and someone who remains on the bridge will hear a decreased pitch or frequency as the source is moving away from the stationary listener as per the Dooplers effect. Hence, the pitch will progressively lower as the source is moving away from the observer.

4 0
3 years ago
Read 2 more answers
A person swings a 0.546-kg tether ball tied to a 4.56-m rope in an approximately horizontal circle. If the maximum tension the r
Murrr4er [49]

Answer:

2.1 rad/s

Explanation:

Given that,

Mass of a tether ball, m = 0.546 kg

Length of a rope, l =  4.56 m

The maximum tension the rope can withstand before breaking is 11.0 N

We need to find the maximum angular speed of the ball. Let v is the linear velocity. The maximum tension is balanced by the centripetal force acting on it. It can be given by :

F=\dfrac{mv^2}{r}\\\\v=\sqrt{\dfrac{Fr}{m}} \\\\v=\sqrt{\dfrac{11\times 4.56}{0.546}} \\\\=9.584\ m/s

Let \omega is the angular speed of the ball. The relation between the angular speed and angular velocity is given by :

v=r\omega\\\\\omega=\dfrac{v}{r}\\\\=\dfrac{9.584}{4.56}\\\\=2.1\ rad/s

So, the maximum angular speed of the ball is 2.1 rad/s.

4 0
3 years ago
Psychophysics is a discipline in psychology that focuses solely on the identification of stimuli. T F
Rzqust [24]
Hi There,

  
This is False.
Hope this helped!
3 0
3 years ago
Read 2 more answers
A 300 g ball and a 600 g ball are connected by a 40-cm-lon massless, rigid rod. The structure rotates about its center of me at
Readme [11.4K]

Answer:

 KE = 1.75 J

Explanation:

given,

mass of ball, m₁ = 300 g = 0.3 Kg

mass of ball 2, m₂ = 600 g = 0.6 Kg

length of the rod = 40 cm = 0.4 m

Angular speed = 100 rpm= 100\times \dfrac{2\pi}{60}

                         =10.47\ rad/s

now, finding the position of center of mass of the system

    r₁ + r₂ = 0.4 m.....(1)

 equating momentum about center of mass

  m₁r₁ = m₂ r₂

   0.3 x r₁ = 0.6 r₂

   r₁ = 2 r₂

Putting value in equation 1

2 r₂ + r₂ = 0.4

 r₂ = 0.4/3

 r₁ = 0.8/3

now, calculation of rotational energy

KE = \dfrac{1}{2}I_1\omega^2+\dfrac{1}{2}I_2\omega^2

KE = \dfrac{1}{2}\omega^2 (I_1 +I_2)

KE = \dfrac{1}{2}\omega^2 (m_1r_1^2 +m_2r^2_2)

KE = \dfrac{1}{2}\times 10.47^2(0.3\times (0.8/3)^2 +0.6\times (0.4/3)^2)

 KE = 1.75 J

the rotational kinetic energy is equal to 1.75 J

7 0
3 years ago
Can any kind soul help me please​
Alex

Answer:

I) 420000J

ii)

Explanation:

(I) so you can use the formula for quantity of heat then substitute the values given

formula-Q=mc∆9

3 0
3 years ago
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