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-Dominant- [34]
3 years ago
5

What is the age of a sample if there are 6 grams of an element that have not decayed outof an original 24 grams and has a half-l

ife of 8yrs a. 8yrs b. 50yrs c. 29yrs d. 16yrs
Physics
1 answer:
amid [387]3 years ago
8 0

Answer:

d ) 16 years

Explanation:

If n be number of half years passed then

[tex]\frac{m}{m_0} =\sqrt[n]{\frac{1}{2} }[/tex]

m is mass undecayed m₀ is original mass

Here m = 6 g

m₀ =24 g

Putting these values

\frac{6}{24} =\sqrt[n]{\frac{1}{2} }

n = 2 half lives

age = 2 x 8 = 16 years

= 16 years

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Acceleration is defined as the change in velocity divided by
denpristay [2]

Answer:

Time elapsed

Explanation:

Acceleration is a vector quantity. It is defined as:

a=\frac{v-u}{t}

where

v is the final velocity

u is the initial velocity

t is the time elapsed

Acceleration is measured in meters per second squared (m/s^2). It must be noticed that acceleration is a vector, so it also has a direction. In particular:

- when acceleration is negative, it means that the object is slowing down, so acceleration is in opposite direction to the velocity

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3 0
2 years ago
A student has a small metal sphere that hangs from an insulating string. The student, in seeking to determine the charge on the
Leokris [45]

Answer:

the answer the correct one is c

Explanation:

Electric charges of different signs attract and those of the same sign repel. In addition, there are two types of insulating bodies, where the loads are fixed (immobile) and metallic (with mobile loads.

Let's analyze the situation presented

* A rod with positive approaches and the sphere is attracted, so the charge on the sphere is negative

* A rod with a negative charge approaches and the sphere is attracted, therefore the charge of the sphere must be positive.

For this to happen, the sphere must be unloaded and the charge that creates the phenomenon are induced charges because the mobile charges of the same sign as the sphere are repelled.

when checking the answer the correct one is c

8 0
2 years ago
The rate (in mg carbon/m3/h) at which photosynthesis takes place for a species of phytoplankton is modeled by the function P = 9
Ivanshal [37]

Answer:

At light intensity I = 3, is P a maximum

Explanation:

Given:

P=\frac{90I}{I^2+I+9}

now differentiating the above equation with respect to Intensity 'I' we get

\frac{dp}{dI}=\frac{(I^2+I+9).\frac{d(90I)}{dI}-90I.\frac{d((I^2+I+9)}{dI}}{(I^2+I+9)^2}

or

\frac{dp}{dI}=\frac{(I^2+I+9).90-90I.(2I+1)}{(I^2+I+9)^2}

or

\frac{dp}{dI}=\frac{90I^2+90I+810)-(180I^2+90I)}{(I^2+I+9)^2}

or

\frac{dp}{dI}=\frac{-90I^2+810)}{(I^2+I+9)^2}

Now for the maxima \frac{dP}{dI}=0

thus,

0=\frac{-90I^2+810)}{(I^2+I+9)^2}

or

-90I^2+810=0

or

I^2=\frac{810}{90}

or

I^2=9

or

I = 3

thus, <u>for the value of intensity I = 3, the P is maximum</u>

at I = 3

P=\frac{90\times3}{3^2+3+9}

or

P=\frac{270}{21}

or

P=12.85

5 0
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Answer:

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4 0
3 years ago
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SSSSS [86.1K]

Answer:

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3 0
2 years ago
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