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Oksana_A [137]
3 years ago
9

Evaluate the expression for c = -19. C + 15 =

Mathematics
2 answers:
boyakko [2]3 years ago
4 0
Answer is -4
-19 + 15 = -4
KonstantinChe [14]3 years ago
3 0

Answer:

the Answer is -4

Step-by-step explanation:

since you add 15 to -19 you get -4

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Write an equation of the line that is parallel to 5x + 20y = 10 and passes through the point (8, 3).
Serga [27]
20y=-5x+10
y=-1/4x+1/2
y-3=-1/4(x-8)
y-3=-1/4x+2
d. y = -1/4x + 5
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3 years ago
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Is (x +1) a factor of <br> f(x) = x3 + 2x2 −5x − 6 ?<br><br> Yes <br> No
sertanlavr [38]

Answer:

Yes.

Step-by-step explanation:

You can find it out by factoring but ill do it easier way.

(x + 1 ) = 0 put the first and second equation to 0

x = -1

x³ + 2x² - 5x - 6 = 0  Now plug in the x in the equation

(-1)³ + 2(-1)² - 5(-1) - 6 = 0

0 = 0

so (x + 1) is a factor.

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3 years ago
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Ryan fills a bath with
S_A_V [24]

Answer:

38.8 litres

Step-by-step explanation:

22.6 + 18.7 = 41.3

41.3 - 2.5 = 38.8

38.8 litres

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2 years ago
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The sum of three different numbers is 18 if every number is a prime number what are the three numbers
Aleks04 [339]
<span>it would be 5+2+11 because a lll number are prime</span>
5 0
3 years ago
7. In a state lottery, a player must choose 8 of the numbers from 1 to 40. The lottery commission then performs an experiment th
Vlad1618 [11]

Answer:a) P(8 of the players numbers are drawn)=1.3×10^-8

b) P(7 of the players number are drrawn)=3.33×10^-c) P(at least 6 of the players number were drawn)=1.84×10^-4

Step-by-step explanation:

Players has 8 combinations of numbers from 1-40. The outcome S contains all the combinations of 8 out of 40

a) P(8 of the players numbers are drawn)= 1/40/8= 1.3×10^-8

There are one in hundred million chances that the draw numbers are precisely the chosen ones.

b) Number of ways of drawing 78 selected numbers from 1-40=8×(40-7)

8×32

P(7 of the players number are drawn)=8×32/40 =3.33×10^-6.

There are approximately 300,000 chances that 7 of the players numbers are chosen

c) P(at least 6 players numbers are drawn)= 32/2×(8/6) ways to draw.

P(at least 6 players numbers are drawn)=P(all 8 chosen are drawn)+P(7 players numbers drawn)+P(6 chosen are drawn) = 1+ 8 x32/40/8 +[8\6 ×32/2]

P(at least 6 players numbers are drawn) = 1.84×10^-4.

There are approximately 5400chances that at least6 of the numbers drawn are chosen by the player.

5 0
3 years ago
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