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iVinArrow [24]
3 years ago
7

A circuit component with a high resistance will have a low electric current.

Physics
1 answer:
Zepler [3.9K]3 years ago
6 0
You haven't said what 'high' resistance or 'low' current means, so there's way not enough info to nail the statement as true or false. The most precise answer is "certainly could be but not necessarily". Anyway, the current in the circuit depends on BOTH the resistance AND the voltage. So without knowing the voltage too, you can't say anything about the current.
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Segmented mirrors sag under their own weight. their optical shape must be controlled by computer-driven thrusters under the mirr
madam [21]
Active Optics.


Hope that helps, Good luck! (:
6 0
3 years ago
A group of friends wants to go to the amusement park. They have no more
Mumz [18]

Answer:

p ≤ 8

Explanation:

Let's go over what we know that can help us build an inequality:

we know that these friends can spend no <em>more </em>than $325, meaning that they can either spend exactly $325, or they could spend less. This is our first clue, that one side of the inequality will be 325, and that the inequality sign will be <em>less than or equal to </em>( ≤ ) :

amount spent ≤ 325

Now, we want to figure out how many people can go (p)--but there's something we need to consider first--the parking.

Assuming that all friends take one car, we know we will have 11 dollars less to spend on admission (you can write this two ways).

amount spent on tickets + 11 ≤ 325

or, we can simplify it:

amount spent on tickets + 11 ≤ 325

                                          - 11     -11

amount spent on tickets ≤ 314

(I will be using the second way, you could always plug it back into the first way though)

now, we know that each "p" that we include will be multiplied by 39.25

         <em>Why?  Imagine we have one p (one person), they will cost 39.25, so we could write that as (p · 39.25) ,  ( 1· 39.25 ) -- we use × because that's how many </em><em>times</em><em> we're adding the number.  If we have two p, we could write it as (2p · 39.25)--there's an easier way to do this though</em>

<em />

So, we can write "p" to stand for all possible values of p possible,

p · 39.25 ≤ 314                  (we write this slightly differently):

39.25p ≤ 314          

Now, let's simplify!

   39.25p ≤ 314          

÷ 39.25     ÷ 39.25  (divide by 39.25 to isolate p)

          p   ≤   8

So, we know that the number of friends admitted must be less than or equal to 8, expressed as:

p ≤ 8

hope this helps! let me know if you need clarification on anything :)

5 0
2 years ago
Read 2 more answers
PLEASE HELP
kogti [31]

Answer:

C. nuclear to electrical

6 0
3 years ago
Read 2 more answers
Explain what differentiates the Earth’s crust and lithosphere.
Allisa [31]

Answer:

What is the difference between the crust and lithosphere? The crust (whether continental or oceanic) is the thin layer of distinctive chemical composition overlying the ultramafic upper mantle. ... The lithosphere is the rigid outer layer of the Earth required by plate tectonic theory.

Explanation:

Hope this helps!

4 0
3 years ago
Read 2 more answers
What is the magnitude and direction of the electric field atradiaConsider a coaxial conducting cable consisting of a conductingr
Alexxx [7]

Answer:

 E = 9.4 10⁶ N / C ,     The field goes from the inner cylinder to the outside

Explanation:

The best way to work this problem is with Gauss's law

             Ф = E. dA = qint / ε₀

 

We must define a Gaussian surface, which takes advantage of the symmetry of the problem. We select a cylinder with the faces perpendicular to the coaxial.

The flow on the faces is zero, since the field goes in the radial direction of the cylinders.

The area of ​​the cylinder is the length of the circle along the length of the cable

         dA = 2π dr L

          A = 2π r L

They indicate that the distance at which we must calculate the field is

         r = 5 R₁

         r = 5 1.3

         r = 6.5 mm

The radius of the outer shell is

         r₂ = 10 R₁

         r₂ = 10 1.3

         r₂ = 13 mm

         r₂ > r

When comparing these two values ​​we see that the field must be calculated between the two housings.

Gauss's law states that the charge is on the outside of the Gaussian surface does not contribute to the field, the charged on the inside of the surface is

         λ = q / L

         Qint = λ L

Let's replace

      E 2π r L = λ L /ε₀

       E = 1 / 2piε₀  λ / r

Let's calculate

         E = 1 / 2pi 8.85 10⁻¹²  3.4 10-12 / 6.5 10-3

         E = 9.4 10⁶ N / C

The field goes from the inner cylinder to the outside

5 0
3 years ago
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