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3 years ago

Explain what an exoskeleton is and what it is made of.

1 answer:

5 0

The bodies of arthropods are supported, not by internal bones, but by a hardened exoskeleton made of chitin, a substance produced by many non-arthropods as well. In arthropods, the nonliving exoskeleton is like a form-fitting suit of armor. It is produced by the "skin" and then hardens into a protective outer-covering.

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Hello, I want to ask. . anyone knows the answer.

stealth61 [152]

I would say D. because you round to the nearest whole number and 0.04 is way less than 0.5 which is a good rounding up number.

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3 years ago

Ill give you points if you answer this question

jonny [76]

Animal testing is unreliable because the results may not be precise to what it might do to humans because our bodies do not work the same.

it is cruel to the animals that are being forced to be test subject because they are forced to put their life in the line and they don’t have any say in it because they don’t speak English. (More than 100 million animals die a year while testing products)

This is affecting the earth because the animals are given severe abdominal pain, diarrhea, seizures, and many more awful side effects. The chemicals given to animals include pesticides, dyes, cosmetics and many other harmful things
(Let me know if this helped)

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3 years ago

In the diagram, above, marker F is pointing to a __________, which are formed when meanders wear away at a narrow point and a po

castortr0y [4]

The answer is oxbow lake

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3 years ago

Read 2 more answers

A man strikes one end of a thin rod with a hammer. The speed of sound in the rod is 15 times the speed of sound in air. A woman,

lina2011 [118]

Answer:

44.1 m

Explanation:

Given:

$V_a$ = speed of sound in air = 343 m/s
$V_r$ = speed of sound in the rod = $15V_a$
$\Delta t$ = times interval between the hearing the sound twice = 0.12 s

Assumptions:

$l$ = length of the rod
$t$ = time taken by the sound to travel through the rod
$T$ = time taken by the sound to travel to through air to the same point = $t+\Delta t = t+0.12\ s$

We know that the distance traveled by the sound in a particular medium is equal to the product of the speed of sound in that medium and the time taken.

For traveling sound through the rod, we have

$l=V_r t\\\Rightarrow t = \dfrac{l}{V_r}$ ..........eqn(1)

For traveling sound through the air to the women ear for traveling the same distance, we have

$l=V_aT\\\Rightarrow l=V_a(t+0.12)\\\Rightarrow l=V_a(\dfrac{l}{V_r}+0.12)\,\,\,\,\,\,(\textrm{From eqn (1)})\\\Rightarrow l=V_a(\dfrac{l}{15V_a}+0.12)\\\Rightarrow l=\dfrac{l}{15}+0.12V_a\\\Rightarrow l-\dfrac{l}{15}=0.12V_a\\\Rightarrow \dfrac{14l}{15}=0.12V_a\\\Rightarrow l = \dfrac{15}{14}\times 0.12V_a\\\Rightarrow l = \dfrac{15}{14}\times 0.12\times 343\\\Rightarrow l = \dfrac{15}{14}\times 0.12\times 343\\\Rightarrow l = 44.1\ m$

Hence, the length of the rod is 44.1 m.

4 0

3 years ago

A ball is kicked horizontally at 4.6 m/s off of a cliff 13.4 m high. How far from the cliff will it land.

Mekhanik [1.2K]

<h3>Answer:</h3>

7.53 m

<h3>Explanation:</h3>

We are given:

Initial Horizontal Velocity of the Ball = 4.6 m/s

Initial Vertical Velocity of the Ball = 0 m/s

Height from which ball is kicked = 13.4 m

Time taken by the ball to reach the ground:

The ball has an initial vertical velocity of 0 m/s

it also has a downward acceleration of 10 m/s² due to gravity

Solving for the time taken:

s = ut + 1/2(at²) [second equation of motion]

replacing the values

13.4 = (0)(t) + 1/2 (10)(t²)

13.4 = 5t²

t² = 13.4/5 [dividing both sides by 5]

t² = 2.68

t = 1.637 seconds [taking the square root of both sides]

Horizontal distance covered by the ball:

Since there are no horizontal opposing forces on the ball,

the ball will more horizontally at a velocity of 4.6 m/s until it hits the ground

We calculated that the ball will hit the ground in 1.637 seconds

Distance covered:

s = ut + 1/2 (at²) [seconds equation of motion]

s = ut [since a = 0m/s² in the horizontal plane]

replacing the values

s = 4.6 * 1.637

s = 7.53 m

Hence, the ball landed 7.53 m from the cliff

5 0

3 years ago