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Morgarella [4.7K]
3 years ago
14

The length of a retanle is twice the width plus 10. if the perimenter of the rectangle must be 200 inches what is the maimumarea

of the rectange?
Physics
1 answer:
timurjin [86]3 years ago
5 0
<h2>Area = 2100 inch²</h2>

Explanation:

The length of a rectangle is twice the width plus 10

Let L be the length and W be the width.

               L = 2W + 10

The perimeter of the rectangle must be 200 inches

           Perimeter = 2 (L+W) = 200

                              2(2W+10+W) = 200

                                 3W + 10 = 100

                                 3W = 90

                                    W = 30 inches

                 L = 2 x 30 + 10 = 70 inches

Area = Length x Width

Area = 30 x 70

Area = 2100 inch²

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Explanation:

The function:

f(x) = 8x^3-3x^2-5x^8

The left and right ends would be indicated when x is changed to -x. When this is substituted, the change is indicated by the first term because only the degree of first term is odd.

Let the left hand side be donated by -x.

Then,

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