Step-by-step explanation:
a)
well, it is kind of written already :
228 miles and 6 gallons.
so, miles/gallon = 228/6 = 38 miles/gallon.
b)
it is not mentioned, but I guess we have to assume that he got the same miles/gallon ratio on this trip as well.
so, again
38 miles/gallon
and he used 9 gallons.
so, he drove 38×9 = 342 miles
D is the answer as the both have solution x=-2 y=3
14x=-28 12(-2)-3y=-33
x=-2 -3y=-9
y=3
from the given equation
4x-y=11 eq 1
2x+3y=5 eq 2
x=y-11/4 from equation 1
subsitute this value of x in equation 2
2(y-11/4)+3y=5
y-11+6y=10
7y-11=10
y=3
subsitude this value of y in equation (x=y-11/4)
so x= -2
thus same solution so ANSWER IS D
Answer:
43.82 mph
266.67 feet
Step-by-step explanation:
Given :
S = √30fl
S = speed of car
f = drag Coefficient
l = Length of skid mark
If f = 0.8 ; l = 80 feets
s = √30fl
s = √(30*0.8*80)
s = √1920
s = 43.817
s = 43.82 mph
B.)
s = 80 mph
f = 0.8
s = √30fl
80 = √30*0.8*l
80 = √24l
Square both sides
80² = 24l
6400 = 24l
l = 6400/24
l = 266.67 feets
