All categories

2 years ago

There were 5 people who bought tickets to a football game.They bought 3 tickets each.How many tickets were bought in all

Mathematics

2 answers:

ladessa [460]2 years ago

7 0

15 people bought tickets lol

VLD [36.1K]2 years ago

6 0

Easy! 5×3 tickets which equals 15 tickets in all!

You might be interested in

6. Calculate the area of the octagon in the figure below.

Kryger [21]

Answer:

$41\text{ [units squared]}$

Step-by-step explanation:

The octagon is irregular, meaning not all sides have equal length. However, we can break it up into other shapes to find the area.

The octagon shown in the figure is a composite figure as it's composed of other shapes. In the octagon, let's break it up into:

4 triangles (corners)
3 rectangles (one in the middle, two on top after you remove triangles)

Formulas:

Area of rectangle with length $l$ and width $w$ : $A=lw$
Area of triangle with base $b$ and height $h$ : $A=\frac{1}{2}bh$

Area of triangles:

All four triangles we broke the octagon into are congruent. Each has a base of 2 and a height of 2.

Thus, the total area of one is $A=\frac{1}{2}\cdot 2\cdot 2=2\text{ square units}$

The area of all four is then $2\cdot 4=8$ units squared.

Area of rectangles:

The two smaller rectangles are also congruent. Each has a length of 3 and a width of 2. Therefore, each of them have an area of $3\cdot 2=6$ units squared, and the both of them have a total area of $6\cdot 2=12$ units squared.

The last rectangle has a width of 7 and a height of 3 for a total area of $7\cdot 3=21$ units squared.

Therefore, the area of the entire octagon is $8+12+21=\boxed{41\text{ [units squared]}}$

4 0

3 years ago

The area of a rectangle is 12.65 m^2. the length measures 5.5 m. what is the width of the rectangle?

Nat2105 [25]

Answer:

The width of the rectangle is 2.3 m

Step-by-step explanation:

Now, when we are asked to find the area of the rectangle, we will use the formula: $Area= length * width$ . We should be given with at least two values, and then we can use the above formula and can find the third variable.

Now, we are given that the area of a rectangle is 12.65 $m^2$ and the length measures 5.5 m

So the width is given as:

$Area= length * width\\\Rightarrow 12.56= 5.5 * width\\\Rightarrow width= \frac{12.56}{5.5}\\\Rightarrow width=2.3 ~m$

So this is the required with of the rectangle.

4 0

3 years ago

Read 2 more answers

Aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

julsineya [31]

The answer is -8/1 two negatives equals negative which would be -11 then subtract positive 3 equals-8

7 0

1 year ago

Evaluate the function at the given numbers( correct to six decimal places). Use the results to guess the value of the limit or e

netineya [11]

Answer:

Value of the limit is 0.5.

Step-by-step explanation:

Given,

$F(x)=\frac{e^x-1-x}{x^2}$

When,

$x=1,F(1)=frac{e^1-1-1}{1}=e-2=0.718281$

$x=0.5, F(0.5)=\frac{e^0.5-1-0.5}{(0.5)^2}=0.594885$

$x=0.1, F(0.1)=\frac{e^0.1-1-0.1}{(0.1)^2}=0.517091$

$x=0.05, F(0.05)=\frac{e^0.05-1-0.05}{(0.05)^2}=0.508438$

$x=0.01, F(0.01)=\frac{e^0.01-1-0.01}{(0.01)^2}=0.501670 \hfill (1)$

Correct upto six decimal places.

Now,

$\lim_{x\to 0}F(x)=\lim_{x\to 0}\frac{e^x-1-x}{x^2}$ $(\frac{0}{0})$ form, applying L-Hospital rule that is differentiating numerator and denominator we get,

$\lim_{x\to 0}F(x)$

$=\lim_{x\to 0}\frac{e^x-1}{2x}$ $(\frac{0}{0})$ form.

$=\lim_{x\to 0}\frac{e^x}{2}=\frac{1}{2}=0.5\hfill (2)$

Limit exist and is 0.5. That is according to (1) we can see as the value of x lesser than 1 and tending to near 0, value of the function decreases respectively. And from (2) it shows ultimately it decreases and reach at 0.5, consider as limit point of F(x).

8 0

3 years ago

Convert 67.5 cu ft to cubic yards.

Diano4ka-milaya [45]

I got 2.500 repeating :)

6 0

3 years ago

Read 2 more answers