Answer:
![41\text{ [units squared]}](https://tex.z-dn.net/?f=41%5Ctext%7B%20%5Bunits%20squared%5D%7D)
Step-by-step explanation:
The octagon is irregular, meaning not all sides have equal length. However, we can break it up into other shapes to find the area.
The octagon shown in the figure is a composite figure as it's composed of other shapes. In the octagon, let's break it up into:
- 4 triangles (corners)
- 3 rectangles (one in the middle, two on top after you remove triangles)
<u>Formulas</u>:
- Area of rectangle with length
and width
:
- Area of triangle with base
and height
:
<u>Area of triangles</u>:
All four triangles we broke the octagon into are congruent. Each has a base of 2 and a height of 2.
Thus, the total area of one is 
The area of all four is then
units squared.
<u>Area of rectangles</u>:
The two smaller rectangles are also congruent. Each has a length of 3 and a width of 2. Therefore, each of them have an area of
units squared, and the both of them have a total area of
units squared.
The last rectangle has a width of 7 and a height of 3 for a total area of
units squared.
Therefore, the area of the entire octagon is ![8+12+21=\boxed{41\text{ [units squared]}}](https://tex.z-dn.net/?f=8%2B12%2B21%3D%5Cboxed%7B41%5Ctext%7B%20%5Bunits%20squared%5D%7D%7D)
Answer:
The width of the rectangle is 2.3 m
Step-by-step explanation:
Now, when we are asked to find the area of the rectangle, we will use the formula:
. We should be given with at least two values, and then we can use the above formula and can find the third variable.
Now, we are given that the area of a rectangle is 12.65
and the length measures 5.5 m
So the width is given as:

So this is the required with of the rectangle.
The answer is -8/1 two negatives equals negative which would be -11 then subtract positive 3 equals-8
Answer:
Value of the limit is 0.5.
Step-by-step explanation:
Given,

When,





Correct upto six decimal places.
Now,
form, applying L-Hospital rule that is differentiating numerator and denominator we get,

form.

Limit exist and is 0.5. That is according to (1) we can see as the value of x lesser than 1 and tending to near 0, value of the function decreases respectively. And from (2) it shows ultimately it decreases and reach at 0.5, consider as limit point of F(x).