You first simplify the expression using PEMDAS
-2x^3-10x^2+2x^3-10x^2+x
then combine like terms,
(-2x^3+2x^3), (-10x^2-10x^2), x
cancels out^
so the answer would be -20x^2+x

3 0

3 years ago

Solve the equation by Completing the Square<br> x2 – 10x + 13 = 0

user100 [1]

Answer:

$x=5+\sqrt{12}$

$x=5-\sqrt{12}$

Step-by-step explanation:

$x^2-10x+13=0$

$x^2-10x=-13$

$x^2-10x+(\frac{10}{2})^2 =-13+(\frac{10}{2})^2$

$x^2-10x+(5)^2=-13+(5)^2$

$x^2-10x+25=-13+25\\x^2-10x+25=12$

Factor.

$(x-5)^2=12$

Extract the square root.

$x-5=\frac{+}{} \sqrt{12}$

Add 5

$x=5+\sqrt{12}$

$x=5-\sqrt{12}$

4 0

3 years ago

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a parabolic lamp is facing due east. The bulb (located at the focus) is 8 inches away from the vertex (located at the origin). t

True [87]

9514 1404 393

Answer:

3 1/8 inches

Step-by-step explanation:

For focus-vertex distance p, the equation of the parabola can be written ...

y = x^2/(4p)

Here, we have p=8. We want to find the value of y when x=10 (the radius of the dish). That is ...

y = (10^2)/(4·8) = 100/32 = 3 1/8

The dish is 3 1/8 inches deep.

7 0

2 years ago

!!!!!!!!!! PLEASE HELP IM SO FRUSTRATED

Alinara [238K]

Answer:

Step-by-step explanation:

4 0

2 years ago

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