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Mashutka [201]
3 years ago
10

PLZ HELP

Mathematics
1 answer:
Agata [3.3K]3 years ago
4 0

Answer:

\frac{5x^{2} }{12}

Step-by-step explanation:

Given: Height: x

          Base: \frac{5x}{6}

Now, finding the area of triangle.

Formula; Area of triangle= \frac{1}{2} \times base\times height

⇒ Area of triangle= \frac{1}{2}\times \frac{5x}{6} \times x

⇒ Area of triangle= \frac{5x^{2} }{12}

Hence, area of triangle= \frac{5x^{2} }{12}

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Find the value of x.<br> B<br> 10-X<br> 3<br> D<br> х<br> 2.<br> A<br> С<br> x = [?]
Nuetrik [128]

Answer:

3/(10-x) = 5/(10-x+x)

3/(10-x) = 1/2

6 = 10-x

x = 4

Hope this helps!

7 0
3 years ago
the spoke of a wheel reaches from the center of the wheel to its rim with circumference of a rim is 42 inches how long each spok
Virty [35]
The constant π is defined as the ratio of the circumference of a circle with respect to its diameter, mathematically:

π=C/d  which can be rearranged to

C=πd

Since the diameter is equal to twice the radius of the circle, ie d=2r

C=2πr  dividing both sides by 2π gives you:

r=C/(2π), the "spoke" in our problem is equal to the radius of a circle, and we are told that C=42in so:

r=42/(2π) in

r=21/π in

r≈6.68 in (to nearest hundredth of an inch)
7 0
4 years ago
Find thr area of this shape
borishaifa [10]
I'm not sure if this is correct,
but, I got:
130cm x 100cm ?
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8 0
3 years ago
Estimate each percent 67%of 208
Alex_Xolod [135]
139.36
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7 0
3 years ago
Read 2 more answers
Which equation can be used to find the number of fish in the pond on June 1?
olga_2 [115]

Answer: The required equation is f-52=63 and the number of fishes in the pond on June 1 = 115


Step-by-step explanation:

Given: The number of fishes in pond on July 1 = 63

Also, it is said that the number of fishes in pond on July 1 is 52 fewer(lesser) than the number of fishes in pond on June 1.

Let f be the number of fishes in pounds on June 1.

then the required equation will be

f-52=63

Now, add 52 on both the sides  of the equation, we get

f=63+52\\\Rightarrow\ f=115


3 0
4 years ago
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