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3 years ago

What type of graph is useful when depicting piece rates?

Mathematics

2 answers:

iren [92.7K]3 years ago

6 0

Answer:

C- Scatter Plot

Step-by-step explanation:

frutty [35]3 years ago

3 0

Answer: Scatter plot

Step-by-step explanation: Because I looked it up

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Enter the values for the highlighted variables to

kotegsom [21]

Answer:

a= -1

b=-9

c=9

d=3

e=3

f=2

g=1.5

Step-by-step explanation:

8 0

3 years ago

What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove

wolverine [178]

Answer:

The solutions are:

$b=0,\:b=4$

Step-by-step explanation:

Considering the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

Solving the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

$\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c$

$5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2$

$5b^3-10=6b^3-4b^2-10$

$\mathrm{Switch\:sides}$

$6b^3-4b^2-10=5b^3-10$

$6b^3-4b^2-10+10=5b^3-10+10$

$6b^3-4b^2=5b^3$

$\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}$

$6b^3-4b^2-5b^3=5b^3-5b^3$

$b^3-4b^2=0$

$Using\:the\:Zero\:Factor\:Principle:$ $if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

So,

$b=0,b-4=0$

$b=0,b=4$

Therefore, the solutions are:

$b=0,\:b=4$

4 0

3 years ago

Read 2 more answers

Please help me with these questions.

guajiro [1.7K]

There's no questions?

7 0

3 years ago

Divide by 12 nd equal 14

ICE Princess25 [194]

170 dived by 12 is 14

7 0

3 years ago

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If tan θ = 3/2 and cos θ < 0, use the fundamental identities to evaluate the other five trig functions of θ.

notsponge [240]

Use the Pythagorean theorem, tan is y/x so y = -3 and x= -2. Because cos is negative and R is always positive. You need to find R- which is the hypotenuse;
3^2 + 2^2 = r^2
9 + 4 = r^2
13 = r^2
√13 = r.

So you already have tan<span>θ,
cot</span><span>θ= 2/3

sin</span>θ= -3/√13 BUT
you have to rationalize, so you get -3 √13/ 13

cscθ= √13/ -3

cosθ= -2/ √13 BUT
you have to rationalize, so you get -2√13/ 13

secθ= √13/ -2

4 0

3 years ago

Read 2 more answers