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Sati [7]
3 years ago
10

On July 15, 2004, NASA launched the Aura spacecraft to study the earth's climate and atmosphere. This satellite was injected int

o an orbit 705 km above the earth's surface, and we shall assume a circular orbit.
(a) How many hours does it take this satellite to make one orbit?


(b) How fast (in km/s) is the Aura spacecraft moving?
Physics
1 answer:
Reika [66]3 years ago
7 0
On the earth surface g = GM/R^2
 And at the hieight h
 g" = GM/ [R+h] ^2
 g" = R^2/ [ R+h]^2 * g
 g" = {R/ [ R+h] }^2 * g
 g" = {6378/ 7083}^2 * 9.81 = 7.95 m/s^2
 --------------------------------------
T^2 = 4π^2 (R+h) /g"
T^2 = 4π^2 *7083 /7.95 
T = 187.54s = 0.052 hour.
 ========================
 Part B
 v = 2*π *[R+h] / T
 v = 2*π *[7.083] / 187.54s
 v = 0.24 km /s 
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Answer:

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Explanation:

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Flow Speed at the inlet pipe will be given by using Continuity Equation

Q_{1}=Q_{2}

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v_{1}=0.46\times\dfrac{(0.016256)^2}{(0.00635)^2}

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Using Bernoulli's Theorem,

P_{1}+\dfrac{1}{2}\rho\times v_{1}^2+\rho gh_{1}=P_{2}+\dfrac{1}{2}\rho\times v_{2}^2+\rho gh_{2}

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Explanation:

The formular for combined focal length (F) is given as;

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