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torisob [31]
3 years ago
13

Sino tao ang gutom?A.youB.mama mo!C.tamod​

Physics
1 answer:
Fiesta28 [93]3 years ago
5 0
The answer to that question is c. tamod
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A block of wood is floating in water; it is depressed slightly and then released to oscillate up and down. Assume that the top a
Marysya12 [62]

Explanation:

Equilibrium position in y direction:

W = Fb (Weight of the block is equal to buoyant force)

m*g = V*p*g

V under water = A*h

hence,

m = A*h*p

Using Newton 2nd Law

-m*\frac{d^2y}{dt^2} = Fb - W\\\\-m*\frac{d^2y}{dt^2} = p*g*(h+y)*A - A*h*p*g\\\\-A*h*p*\frac{d^2y}{dt^2} = y *p*A*g\\\\\frac{d^2y}{dt^2} + \frac{g}{h} * y =0

Hence, T time period

T = 2*pi*sqrt ( h / g )

4 0
4 years ago
What does the zigzag line in the circuit diagram represent
faust18 [17]
A) An electrical resistor  


Hope that helps, Good luck! (:
6 0
3 years ago
What is the pressure at 5000 km below the surface of the earth
attashe74 [19]

Answer:

The centre of the earth is harder to study than the centre of the sun." Temperatures in the lower mantle the reach around 3,000-3,500 degrees Celsius and the barometer reads about 125 gigapascals, about one and a quarter million times atmospheric pressure.

Explanation:

7 0
3 years ago
Which are ways to improve the design of this experiment? Check all that apply.
forsale [732]
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6 0
3 years ago
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A person observes a firework display for A safe distance of .750 km. Assuming that sound travels at 340 m/s in air what is the t
WINSTONCH [101]

Answer:

t = 2.2 s

Explanation:

Given that,

A person observes a firework display for A safe distance of 0.750 km.

d = 750 m

The speed of sound in air, v = 340 m/s

We need to find the between the person see and hear a firework explosion. let it is t. So, using the formula of speed.

v=\dfrac{d}{t}\\\\t=\dfrac{d}{v}\\\\t=\dfrac{750\ m}{340\ m/s}\\\\t=2.2\ s

So, the required time is 2.2 seconds.

3 0
3 years ago
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