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torisob [31]
3 years ago
13

Sino tao ang gutom?A.youB.mama mo!C.tamod​

Physics
1 answer:
Fiesta28 [93]3 years ago
5 0
The answer to that question is c. tamod
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What shape are the universe’s largest known galaxies? Question 12 options: A.elliptical B.spiral C.There aren't large galaxies!
jeka94

Elliptical shaped galaxies are the universe’s largest known galaxies.

8 0
2 years ago
the force between a planet and a spacecraft is 1 million newtons. whst will the force be iv the spacecraft moves to halfg its or
dybincka [34]

The forces of gravity between two objects are inversely proportional to
the square of the distance between them.  So reducing the distance
by 1/2 means increasing the gravitational force by 2² = 4 times. 
The 1 million newtons becomes 4 million newtons.

Note that this does NOT mean the satellite's altitude above the surface.
When you're calculating gravitational forces, it's the distance between
the centers of the objects.  So the question is a meaningful exercise
only if we use the distance between the satellite and the planet's center.


6 0
3 years ago
A piston in an internal combustion engine applies torque during 150° of each full rotation of the crankshaft to which it is conn
aalyn [17]

Answer:

T=1.566 N.m

Explanation:

Given that:

rotational speed of the scrank shaft, N = 2500 rpm

power produced by one cylinder, P = 410 W

We know, in case of rotational power:

P=\frac{2\pi.N.T}{60}

where: T= torque

Substituting the respective values in the above eq.

410=\frac{2\pi\times2500\times T}{60}

T= \frac{410\times60}{2\pi\times2500}

T=1.566 N.m is the torque applied by the each piston of the engine.

4 0
2 years ago
You are driving at the speed of 33.4 m/s (74.7296 mph) when suddenly the car in front of you (previously traveling at the same s
romanna [79]

Answer:

Part a)

a = - 8.45 m/s/s

Part b)

d = 66 m

Part c)

d = 14.16 m

Explanation:

Part a)

when car apply brakes then the friction force on the car in front of us is given as

F_f = \mu mg

here we need to find deceleration due to friction

a = \frac{F_f}{m}

a = -\mu g

a = -8.45 m/s^2

Part b)

Braking distance of the car is the distance that it move till it stops

so we will have

v_f^2 - v_i^2 = 2ad

0 - 33.4^2 = 2(-8.45)d

d = 66 m

Part c)

Since we know that average reaction time for human is 0.424 s

now we know that during reaction time our car will travel at uniform speed

so we will have

d = vt

d = (33.4) (0.424)

d = 14.16 m

4 0
2 years ago
Calculate the power provided by a 12 volt car battery with a rating of 350 amperes.
mamaluj [8]

Answer:

Option D

4200 W

Explanation:

Power, P is also given as the product of voltage and current, expressed as P=VI

Here, P is power, V is voltage in the xircuit and I is current theough voltage.

Taking 12 V for voltage across and 350A for current across circuit then power will be

P=350*12=4200 W

Therefore, option D is correct.

8 0
2 years ago
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