Answer:
Option D: 1.5in in front of the target
Explanation:
The object distance is 
.
Because the surface is flat, the radius of curvature is infinity .
The incident index is 
and the transmitted index is 
.
The single interface equation is 
Substituting the quantities given in the problem,
The image distance is then 
Therefore, the coin falls 
in front of the target
Answer:
A. continental-oceanic convergent
Explanation:
I knew it couldn't be B because it's oceanic and <em>continental</em>, not oceanic and <em>oceanic</em>.
Next, I noticed the word <em>convergent</em>, which implies "coming together" to me.
I looked it up and noticed the term <em>convergent</em> referred to a plate boundary where a plate slips under (<em>subducted</em>) another, so I knew it was A.
Hopefully, this helps you understand the question better. Have a great day!
Answer:
$21,840
Explanation:
35 hours times 52 weeks - 1820 hours
1820 hours times 12 dollars = $21,840 before taxes
(a) The stone moves by uniform accelerated motion, with constant acceleration
directed downwards, and its initial vertical position at time t=0 is 750 m. So, the vertical position (in meters) at any time t can be written as
(b) The time the stone takes to reach the ground is the time at which the vertical position of the stone becomes zero: y(t)=0. So, we can write
from which we find the time t after which the stone reaches the ground:
(c) The velocity of the stone at time t can be written as
because it is an accelerated motion with initial speed zero. Substituting t=12.37 s, we find the final velocity of the stone:
(d) if the stone has an initial velocity of
, then its law of motion would be
and we can find the time it needs to reach the ground by requiring again y(t)=0:
which has two solutions: one is negative so we neglect it, while the second one is t=11.78 s, so this is the time after which the stone reaches the ground.
