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ehidna [41]
3 years ago
9

Finally, the switch on the electromagnet is reopened. The magnitude of the external magnetic flux through the wire loop ______ (

A. increases, B. decreases, C. remains constant), and there is _______ (A. zero, B. a clockwise, C. a counterclockwise) current induced in the loop (as seen from the left).Enter the letters corresponding to the responses that correctly complete the statement above. For example, if the correct answers are A and C, type A,C________________Now consider the new arrangement shown in the figure. (Figure 2) Note that the orientation of the battery is reversed with respect to the first arrangement you considered. Answer the following questions related to the arrangment with the new battery orientation.
Physics
1 answer:
Natali5045456 [20]3 years ago
5 0
C. Is my best guess!
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BLANK causes movement of an object, whereas BLANK is the work done on an object in a given amount of time.
Setler [38]
The first one is Force & the second one Power.
3 0
4 years ago
Read 2 more answers
Public television station KQED in San Francisco broadcasts a sinusoidal radio signal at a power of 777 kW. Assume that the wave
ehidna [41]

Answer:

A) P = 3.3 × 10^(-11) Pa

B) Amplitude of electric field = 1.931 N/C

Amplitude of magnetic field = 6.44 × 10^(-9) T

C) μ_av = 1.65 × 10^(-11) J/m³

D) 50% each for the electric and magnetic field

Explanation:

A) First of all let's calculate intensity.

I = P_av/A

We are given;

P_av = 777 KW = 777,000 W

Distance = 5 km = 5000 m

Thus;

I = 777000/(2π × 5000²)

I = 0.00495 W/m²

Now, the average pressure would be given by the formula;

P = 2I/C

Where C is speed of light = 3 × 10^(8) m/s

P = (2 × 0.00495)/(3 × 10^(8))

P = 3.3 × 10^(-11) Pa

B) Formula for the amplitude of the electric field is gotten from;

E_max = √[2I/(εo•c)].

Where εo is the Permittivity of free space with a constant value of 8.85 × 10^(−12) c²/N.mm²

I and c remain as before.

Thus;

E_max = √[(2 × 0.00495)/(8.85 × 10^(−12) × 3 × 10^(8))]

E_max = √3.72881355932

E_max = 1.931 N/C

Formula for amplitude of magnetic field is gotten from;

B_max = E_max/c

B_max = 1.931/(3 × 10^(8))

B_max = 6.44 × 10^(-9) T

C) Formula for average density is;

μ_av = εo(E_rms)²

Now, E_rms = E_max/√2

Thus;

E_rms = 1.931/√2

μ_av = 8.85 × 10^(−12) × (1.931/√2)²

μ_av = 1.65 × 10^(-11) J/m³

D) The energy density for the electric and magnetic field is the same. So both of them will have 50% of the energy density.

4 0
3 years ago
A 70-cm-diameter wheel accelerates uniformly from 160rpm to 280rpm in 4.0s. Determine (a) its angular acceleration, and (b) the
poizon [28]

Explanation:

Given that,

Diameter of the wheel, d = 70 cm = 0.7 m

Initial angular speed, \omega_i=160\ rpm=16.75\ rad/s

Final angular speed, \omega_f=280\ rpm=29.32\ rad/s

Time, t = 4 s

(a) Angular acceleration,

\alpha =\dfrac{\omega_f-\omega_i}{t}\\\\\alpha =\dfrac{29.32-16.75}{4}\\\\\alpha =3.14\ rad/s^2

(b) Tangential acceleration is :

a=r\alpha \\\\a=0.35\times 3.14\\\\a=1.085\ m/s^2  

Angular speed of the wheel after 2 seconds is :

\omega_f=\omega_i+\alpha t\\\\\omega_f=16.75+3.14\times 2\\\\\omega_f=23.03\ rad/s

Radial acceleration will be :

a=\omega_f^2r\\\\a=(23.03)^2\times 0.35\\\\a=185.6\ m/s^2

Hence, this is the required solution.

4 0
3 years ago
Give an example of how a bicycle rider would accelerate? Explain the three different ways a bicyclist could
Ostrovityanka [42]

A cyclist can increase the speed of their bike in various ways such as, changing gears, positioning themselves properly, increase the pedalling rate

<h3>Ways in which a cyclist can increase the speed of a bicycle</h3>

Bicycle riders could accelerate/ increase their speed in various ways

  • By Changing the gears and by doing so increasing the speed
  • By Positioning themselves in a streamlined manner, this is so that they become aerodynamic hence they cut across airflow.
  • By increase the rate at which they are pedalling the bicycle.

Learn more about increasing bicycle speed here:

brainly.com/question/13749553

7 0
3 years ago
If the mass of the cement is 15 000 kg, calculate the density of this cement sample in kgm-3
MrRa [10]

Explanation:

Hi there!

Mass of the container (m) = 15000 kg

Also from the figure;

Volume of the container (V) = l*b*h

{ From figure length = 2m , breadth = 1.1m, height = 2.5m}

So,

V = (2*1.1*2.5) m³

= 5.5m³

Then;

Density (d) = m/v

= 15000/5.5

= 2727.27 kgm³

Therefore, the density is 2727.27 kgm³.

Hope it helps!

5 0
2 years ago
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