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GrogVix [38]
3 years ago
8

Each large pizza can feed three teenage boys. How many pizzas would be needed to feed the

Physics
2 answers:
Blababa [14]3 years ago
6 0

Answer:

19 pizzas

Explanation:

1 pizza = 3 boys

=> 56 ÷ 3 = 18.666666666666.. or about 19 pizzas

Xelga [282]3 years ago
4 0
18.666666666666666 or round to 19
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Refraction as in a pencil going into water


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3 years ago
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A 10.0-cm-long uniformly charged plastic rod is sealed inside a plastic bag. The net electric flux through the bag is 7.50 × 10
Rina8888 [55]

Answer:

66.375 x 10⁻⁶ C/m

Explanation:

Using Gauss's law which states that the net electric flux (∅) through a closed surface is the ratio of the enclosed charge (Q) to the permittivity (ε₀) of the medium. This can be represented as ;

∅ = Q / ε₀        -----------------(i)

Where;

∅ = 7.5 x 10⁵ Nm²/C

ε₀ = permittivity of free space (which is air, since it is enclosed in a bag) = 8.85 x 10⁻¹² Nm²/C²

Now, let's first get the charge (Q) by substituting the values above into equation (i) as follows;

7.5 x 10⁵ = Q / (8.85 x 10⁻¹²)

Solve for Q;

Q = 7.5 x 10⁵ x 8.85 x 10⁻¹²

Q = 66.375 x 10⁻⁷ C

Now, we can find the linear charge density (L) which is the ratio of the charge(Q) to the length (l) of the rod. i.e

L = Q / l     ----------------------(ii)

Where;

Q = 66.375 x 10⁻⁷ C

l = length of the rod = 10.0cm = 0.1m

Substitute these values into equation (ii) as follows;

L = 66.375 x 10⁻⁷C / 0.1m

L = 66.375 x 10⁻⁶ C/m

Therefore, the linear charge density (charge per unit length) on the rod is 66.375 x 10⁻⁶ C/m.

3 0
3 years ago
Why is lighting visible before thunder is heard
Tamiku [17]

Answer: Lightning is mostly light and electricity, this light that is hitting is going at a rate of 299,792.458 km per second (or 186,282 miles per second) this is so much compared to sound which only travels at about 761 mph (or approximately 332 meters per second). Fun fact: The lightening you are seeing is that coming back to the cloud because the process happens so fast.

Explanation:

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3 years ago
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A parallel-plate capacitor is formed from two 2.7 cm -diameter electrodes spaced 1.4 mm apart. The electric field strength insid
Andre45 [30]

Answer:

The potential difference between the plates is 8.4\times10^{3}\ V

Explanation:

Given that,

Distance = 1.4 mm

Electric field strength E= 6.0\times10^{6}\ N/C

Let the potential difference is V.

We need to calculate the potential difference between the plates

Using formula of electric field

E=\dfrac{V}{d}

V=Ed

Where, V = potential

d = distance

Put the value into the formula

V=6.0\times10^{6}\times1.4\times10^{-3}

V=8.4\times10^{3}\ V

Hence, The potential difference between the plates is 8.4\times10^{3}\ V

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3 years ago
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Ludmilka [50]

We have volume of gasoline = 14.0 gallon

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So mass flow rate delivered by the gasoline pump in lbm/min = 56.68

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3 years ago
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