Im pretty sure it’s A. temperature
Answer:
This is because it is derived from newtons and metres as shown in the expression;
Explanation:

Given: <span>ω(t) = 8.00 - 0.2*t^2
Differentiating both sides with respect to time we get:
angular acceleration = </span>α(t) = -0.2 * 2 *t
At t = 6.8 sec,
angular acceleration = α(t) = -0.2 * 2 *6.8 = -2.72 rad/s^2
Answer:
The speed of car A before collision is 3.5 km/h.
Explanation:
Mass of car A = 690 kg eastwards
Mass of car B = 520 kg at 74 km/h west wards
Distance, s = 6 m
coefficient of friction = 0.75
Let the speed after collision is v.
Use third equation of motion

Let the initial speed of car A is v'.
Use conservation of momentum
690 x v' - 520 x 74 = (690 + 520) x 33.8
690 v' + 38480 = 40898
v' = 3.5 km/h