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Answer:
inwards when viewing from the left side.
Explanation:
Given:
- radius of the circular loop,
- current in the coil,
- Direction of current is clockwise when viewed from left.
- Distance of wire P from the loop,
- Distance of wire Q from the loop,
- current in each wires P & Q,
Now the magnetic field in coil will be inwards when viewed from left by the Maxwell's right hand thumb rule.
<u>Magnitude is given by:</u>
<u>Now the effect of magnetic field due to wire P at the center of the loop:</u>
(We get the effective distance as 0.4+0.2=0.6 m)
coming out of the loop when viewed from left.
<u>Now the effect of magnetic field due to wire Q at the center of the loop:</u>
(We get the effective distance as 0.8+0.2=1 m)
going in to the loop when viewed from left.
<u>Now the net resultant effect all the magnetic fields:</u>
inwards when viewing from the left side.
Answer:
Explanation:
Let the four charges is q and the side of square is a.
Let the distance of all charges from the centre is d.
AO = BO = CO = DO = d
Potential due to single charge at the centre is Vo.
Potential at the centre due to all charges is
V = Vo + Vo + Vo + Vo = 4 Vo
Electric field due to single charge at centre is Eo.
So, the electric ifled due to all charges at centre is
E = (Eo - Eo) + (Eo - Eo) = 0
