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Alchen [17]
3 years ago
6

PLEASE HELP!!!!!! the independent variable is associated mainly with? A. control and experimental groupsB. the treatment that th

e researcher controls directly C. the result of experiment D. the hypothesis
Physics
2 answers:
Alex_Xolod [135]3 years ago
7 0
The correct answer is B. The independent variable refers to what is being tested by a researcher in an experiment

Hope this helps
aliina [53]3 years ago
6 0

Answer:

B

Explanation:

Apex :)

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If the horse lifts a 50 kilogram mass a vertical distance of 3 meters in 2 seconds, what is the horse’s minimum power output?
yaroslaw [1]

Answer:

735watts

Explanation:

Power = Force*distance/time

Given

Force = mg = 50 * 9.8'

Force = 490N

distance = 3m

time = 2s

Substitute

Power = 490*3/2

Power = 1470/2

Power = 735Watts

Hence the minimum power output is 735watts

7 0
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How does the sun affect the water cycle?
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i think the answer is D.

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What are two types of diffraction?
tino4ka555 [31]
Fresnel and Fraunhofer diffraction. Fresnel diffraction is produced when light from a point source meets an obstacle, the waves are spherical and the pattern observed is a fringed image of the object. Fraunhofer diffraction occurs with plane wave-fronts with the object effectively at infinity. The pattern is in a particular direction and is a fringed image of the source.
7 0
3 years ago
What is the displacement of the particle in the time interval 5 seconds to 8 seconds?
Dmitriy789 [7]
The displacement is the vector with

magnitude
     distance between position at 5 sec and position at 8 sec
and direction
     direction from position at 5 sec to position at 8 sec .

The route followed during the time interval is irrelevant.

      
3 0
3 years ago
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Given that average speed is distance traveled divided by time, determine the values of m and n when the time it takes a beam of
emmainna [20.7K]

Answer:

5,2

Explanation:

From the question we are told that:

Speed of light C=3.0×10^8 m/s.

Generally the equation for Average Speed is mathematically given by

V_{avg}=\frac{d}{t}

Where

d=Distance between the Earth and the sun

d=1.5*10^11m

Therefore

t=\frac{d}{V_{avg}}

t=\frac{1.5*10^11m}{3.0×10^8 m/s.}

t=5*10^2s

Since m and n is given in the form of

m*10^n

Therefore

m=5 & n=2

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3 0
3 years ago
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