Can anybody help me with this?? (Picture included.)

A train is traveling at a speed of 80km/h when the conductor applies the brakes. The train slows with a constant acceleration of

melisa1 [442]

Answer:

d = 493.72 m

Explanation:

Given that,

Initial velocity of the train, u = 80 km/h = 22.22 m/s

Acceleration of the train, a = -0.5 m/s² (negative as it slows down)

Finally brakes are applied, v = 0

We need to find the distance the train travels. Let the distance be d. Using third equation of kinematics to find it.

$v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{0^2-(22.22)^2}{2\times (-0.5)}\\\\d=493.72\ m$

So, the required distance is equal to 493.72 m.

3 0

3 years ago

A microwave oven operates on 1500 W of power and is used for 30 minutes. How

igomit [66]

Answer:

i think the answer is 50 kW.h

8 0

3 years ago

In the following calculations, be sure to express the answer in standard scientific notation with the appropriate number of

Ratling [72]

Answer:

-45,597.07

Explanation:

if not in scientific calculator and yung answer nung sa scientific sa comment na lang dinadownload ko ka eh

4 0

3 years ago

Two cylinders contain the same ideal gas and have the same volume. If the gas molecules in cylinder B have twice the average kin

ipn [44]

Hence, internal energy in cylinder B is twice than that in A.

It is given that two cylinders contain the same ideal gas and have the same volume. If the gas molecules in cylinder B have twice the average kinetic energy as those in cylinder, we need to compare internal energy.

As kinetic energy is directly proportional to temperature, internal energy is also proportional to temperature.

We can say that more the average kinetic energy, more is the internal energy.

Hence, internal energy in cylinder B is twice than that in A.

The ratio in A:B is 1:2.

Learn more about kinetic energy click here brainly.com/question/11067389

#SPJ4

7 0

2 years ago

A car travels at a steady 40.0 m/s around a horizontal curve of radius 200 m. What is the minimum coefficient of static friction

DanielleElmas [232]

Answer:

The minimum coefficient of static friction between the road and the car's tires is 0.816

Option "C"

Explanation:

Given;

velocity of the car, v = 40.0 m/s

radius of horizontal curve, r = 200 m

For a minimum coefficient of static friction between the road and the car's tires that will allow the car to travel at the given speed without sliding, centripetal force must equal frictional force.

$F_{frictional} = F_{centripetal}\\\\\mu mg = \frac{mv^2}{r} \\\\\mu = \frac{v^2}{rg}$

where;

μ is the minimum coefficient of static friction

$\mu = \frac{40^2}{200*9.8} \\\\\mu = 0.816$

Thus, the minimum coefficient of static friction between the road and the car's tires is 0.816

Option "C"

3 0

3 years ago