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2 years ago

How does velocity differ from speed? What changes in motion can result in a change in velocity?

2 answers:

6 0

Any change in motion (direction or speed) is a change in velocity.
Velocity is a vector quantity which means that it has a magnitude and a direction.

Speed, being a scalar quantity, is the rate at which an object covers distance. The average speed is the distance (a scalar quantity) per time ratio. Speed is ignorant of direction. ... The average velocity is the displacement or position change (a vector quantity) per time ratio.

olga55 [171]2 years ago

4 0

-Velocity is the speed of any moving object in a given direction, whilst Speed is the rate of an object's ability to move.
-Velocity can change if the direction or time is changed, the basic equation of velocity is: v = d/t
v - velocity
d - distance
t - time
If one of these factors change, it affects the other.

Hope this answers the question!

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In a ballistic pendulum experiment, projectile 1 results in a maximum height h of the pendulum equal to 2.6 cm. A second project

Trava [24]

Answer:

Second projectile is 1.4 times faster than first projectile.

Explanation:

By linear momentum conservation

Pi = Pf

m x U + M x 0 = (m + M) x V

$U= \dfrac{(m + M)\times V}{m}$

Now Since this projectile + pendulum system rises to height 'h', So using energy conservation:

KEi + PEi = KEf + PEf

PEi = 0, at reference point

KEf = 0, Speed of system zero at height 'h'

$KEi = \dfrac{(m + M)\times V^2}{2}$

PEf = (m + M) g h

So,

$\dfrac{(m + M)\times V^2}{2} + 0 = 0+ (m + M) g h$

$V =\sqrt {2gh}$

So from above value of V

Initial velocity of projectile =U

$U=\dfrac{(M+m)\sqrt{2gh}}{m}$

Now Since mass of projectile and pendulum are constant, So Initial velocity of projectile is proportional to the square root of height swung by pendulum.

Which means

$\dfrac{U_2}{U_1}=\sqrt{\dfrac{h_2}{h_1}}$

$U_2=\sqrt{\dfrac{h_2}{h_1}}\times U_1$

$U_2=\sqrt{\dfrac{5.2}{2.6}}\times U_1$

U₂ = 1.41 U₁

Therefore we can say that ,Second projectile is 1.4 times faster than first projectile.

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1. Si comprimes un globo hasta reducir su volumen a un tercio de su valor original, ¿cuánto aumenta la presión en su interior?

harina [27]

Answer:

See step by step sexplanation

Explanation:

1.-Sabemos que la relación:

P₁ * V₁ = P₂ * V₂

Para una temperatura constante debe mantenerse entonces si el globo se comprime hasta llevarlo a 1/3 de su valor inicial, entonces necesariamente para cumplir con la relación mencionada, la presión aumenta tres veces su valor original

2.-La definición de presión es fuerza por unidad de superficie, entonces la fuerza es determinada por la altura de la columna de liquido en el recipiente y no por la cantidad total de liquido, de acuerdo a esto habrá más presión en la base del florero, ya que la columna de agua tiene más altura.

3.-No se puede estar de acuerdo con el criterio del plomero. En su solución no plantea el aumento de la altura del tanque, para el logro del aumento de la presión que es realmente lo que hay que hacer

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