Answer:
x = 4 ± 5i
Step-by-step explanation:
Just use the quadratic formula (ax²+bx+c=0) like you would for every other quadratic equation. Substitute i² for -1 when you get the square root of a negative number.
a = 1
b = -8
c = 41
Solution is x = (8 ± √(64-4·41)) / 2
x = 4 ± (√-100) / 2
x = 4 ± (√-25·4)/2
x = 4 ± √-25
x = 4 ± √(25i²)
x = 4 ± 5i
1 41/44
first change both into improper fractions
because it's division, flip the second term while changing sign from division to multiplication.
Answer:
Below in bold.
Step-by-step explanation:
No repetition.
There are a total of 7 numbers.
For the number to be even it must end in 0, 2 or 8.
The other 3 numbers will be the number of permutations of 3 from the 6 other numbers.
Number of 4 digit numbers ending in 0
= 6P3 = 6! / 6-3!
= 120.
Now the number could also end in 2 or 8,
so there are 3*120 = 360 4-digit even numbers (no repetition).
With repetition.
There are 3 * 7^3 = 1029 with repetition.
Answer:
ans=<tnp = 45
hope this will be helpful
