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kobusy [5.1K]
3 years ago
9

Which expression shows the prime factorization of 20?

Mathematics
1 answer:
Firlakuza [10]3 years ago
5 0
The expression that lists all numbers in prime numbers would be A. All numbers here are prime numbers, and is in the simplified form, the remaining choices are not in their simplified forms and can be broken down into smaller numbers that multiply to give their value.
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I need help fast please <br><br>Solve this and show steps <br><br>4.5×8-(0.4+9.6-(3.6-1.8))<br>​
valentina_108 [34]

Answer:

27.8

Step-by-step explanation:

You need to do brackets first

3.6-1.8 = 1.8

Then substitute

4.5 x 8- (0.4 + 9.6- 1.8)

0.4+9.6-1.8=8.2

4.5 x 8 - 8.2 =27.8

7 0
2 years ago
Determine the t critical value(s) that will capture the desired t-curve area in each of the following cases: a. Central area 5 .
Flauer [41]

Answer:

a) "=T.INV(0.025,10)" and "=T.INV(1-0.025,10)"

And we got t_{\alpha/2}=-2.228 , t_{1-\alpha/2}=2.228

b)  "=T.INV(0.025,20)" and "=T.INV(1-0.025,20)"

And we got t_{\alpha/2}=-2.086 , t_{1-\alpha/2}=2.086

c) "=T.INV(0.005,20)" and "=T.INV(1-0.005,20)"

And we got t_{\alpha/2}=-2.845 , t_{1-\alpha/2}=2.845

d) "=T.INV(0.005,50)" and "=T.INV(1-0.005,50)"

And we got t_{\alpha/2}=-2.678 , t_{1-\alpha/2}=2.678

e) "=T.INV(1-0.01,25)"

And we got t_{\alpha}= 2.485

f) "=T.INV(0.025,5)"

And we got t_{\alpha}= -2.571

Step-by-step explanation:

Previous concepts

The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".

The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.  

The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."

Solution to the problem

We will use excel in order to find the critical values for this case

Determine the t critical value(s) that will capture the desired t-curve area in each of the following cases:

a. Central area =.95, df = 10

For this case we want 0.95 of the are in the middle so then we have 1-0.95 = 0.05 of the area on the tails. And on each tail we will have \alpha/2=0.025.

We can use the following excel codes:

"=T.INV(0.025,10)" and "=T.INV(1-0.025,10)"

And we got t_{\alpha/2}=-2.228 , t_{1-\alpha/2}=2.228

b. Central area =.95, df = 20

For this case we want 0.95 of the are in the middle so then we have 1-0.95 = 0.05 of the area on the tails. And on each tail we will have \alpha/2=0.025.

We can use the following excel codes:

"=T.INV(0.025,20)" and "=T.INV(1-0.025,20)"

And we got t_{\alpha/2}=-2.086 , t_{1-\alpha/2}=2.086

c. Central area =.99, df = 20

 For this case we want 0.99 of the are in the middle so then we have 1-0.99 = 0.01 of the area on the tails. And on each tail we will have \alpha/2=0.005.

We can use the following excel codes:

"=T.INV(0.005,20)" and "=T.INV(1-0.005,20)"

And we got t_{\alpha/2}=-2.845 , t_{1-\alpha/2}=2.845

d. Central area =.99, df = 50

  For this case we want 0.99 of the are in the middle so then we have 1-0.99 = 0.01 of the area on the tails. And on each tail we will have \alpha/2=0.005.

We can use the following excel codes:

"=T.INV(0.005,50)" and "=T.INV(1-0.005,50)"

And we got t_{\alpha/2}=-2.678 , t_{1-\alpha/2}=2.678

e. Upper-tail area =.01, df = 25

For this case we need on the right tail 0.01 of the area and on the left tail we will have 1-0.01 = 0.99 , that means \alpha =0.01

We can use the following excel code:

"=T.INV(1-0.01,25)"

And we got t_{\alpha}= 2.485

f. Lower-tail area =.025, df = 5

For this case we need on the left tail 0.025 of the area and on the right tail we will have 1-0.025 = 0.975 , that means \alpha =0.025

We can use the following excel code:

"=T.INV(0.025,5)"

And we got t_{\alpha}= -2.571

8 0
3 years ago
Henry solved the equation 3 (m + 2) = 12 + m
wariber [46]

Answer:

Henry derived the value of m correctly

Step-by-step explanation:

insert m into the equation

3(3+2)=12+3

3(5)=15

15=15

Henry derived the value of m correctly

8 0
3 years ago
Toms total payment for his loan was $10,368. What was his monthly payment if he paid it off after making 36 monthly payments?
PilotLPTM [1.2K]
<h3>Answer: D) 288</h3>

=======================================================

Explanation:

Divide the given dollar amount over the 36 months mentioned.

(10368)/(36) = 288 dollars is the monthly payment

36 months = 3 years

4 0
3 years ago
I will mark you brainiest if you can answer this <br> 12 - 13 x ≥38
Shtirlitz [24]
<h3><u>Explanation</u></h3>
  • Given Inequality

12 - 13x \geqslant 38

  • Solve the Inequality for x-term by making x as the subject.

Solving Inequality is almost the same as solving the equation.

- 13x \geqslant 38 - 12 \\  - 13x \geqslant 26

The problem is here. Some people might forget that when we move the negative coefficient to another side, we have to flip/swap or change the sign to opposite. That means we have to change from >= to <=

x \leqslant  \frac{26}{ - 13}  \\ x \leqslant  - 2

  • Answer Check by substituting x = -2 in the Inequality.

12 - 13( - 2) \geqslant 38 \\ 12 + 26 \geqslant 38 \\ 38 \geqslant 38

The Inequality is true for x = -2 and that means it is also true when x is lesser than - 2.

  • Substitute x = -3

12 - 13( - 3) \geqslant 38 \\ 12 + 39 \geqslant 38 \\ 51 \geqslant 38

Notice that if we substitute the number that are lesser or equal to -2, the Inequality will be true.

<h3><u>Answer</u></h3>

<u>\large  \boxed{x \leqslant  - 2}</u>

6 0
3 years ago
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