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VMariaS [17]
3 years ago
12

Solve for x. Show the equation you used and your work.

Mathematics
1 answer:
kirill115 [55]3 years ago
3 0
More information is needed to answer your question.

The answer provided below is on the assumption that |AD| is an angle bisector of <BAC, by Sine rule

\frac{\sin{\angle BAD}}{24}=\frac{\sin{\angle BDA}}{36} \\  \\ \Rightarrow\sin{\angle BAD}=\frac{24\sin{\angle BDA}}{36}

Also,
\frac{\sin{\angle CAD}}{18}=\frac{\sin{\angle CDA}}{x} \\ \\ \Rightarrow\sin{\angle CAD}=\frac{18\sin{\angle CDA}}{x}

But,
\angle BAD=\angle CAD

Thus,
\frac{24\sin{\angle BDA}}{36}=\frac{18\sin{\angle CDA}}{x} \\  \\ x\sin{\angle BDA}=27\sin{\angle CDA}

But, \angle BDA\ and\ \angle CDA are supplementary angles, hence they are equal.

Therefore, x = 27
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