Всяко действие има равно по големина и противоположно по посока противодействие.
Answer:
A. Kinetic energy is converted to electric potential energy, and the proton moves more slowly.
Explanation:
When a moving proton is brought close to a stationary one, the kinetic energy of the moving one is converted to electric potential and the proton moves more slowly.
Kinetic energy is the energy due to the motion of a body. A moving proton will possess this form of energy.
Two protons according to coulombs law will repel each other with an electrostatic force because they both have similar charges. This will increase their electric potential energy of both of them.
Potential energy is the energy at rest of a body. As it increases, the motion of a body will be slower and it will tend towards being stationary.
it’s B (because 20 Is smaller than 50)
Answer:
B) The car at point C has less kinetic energy than the car at point B.
Explanation:
We have two types of energy involved in this situation:
- Gravitational potential energy: this is the energy related to the heigth of the car, and it is given by 
, where m is the mass of the car, g is the gravitational acceleration, and h is the heigth of the car. The potential energy is higher when the car is located higher above the ground.
- Kinetic energy: this is the energy due to the motion of the car, and it is given by 
, where m is the mass of the car and v is its speed. The kinetic energy is higher when the speed of the car is higher.
- The law of conservation of energy states that the total mechanical energy of the car (sum of potential energy and kinetic energy: 
) is constant). This implies that when the car is at a higher point, the kinetic energy is less (because U is larger, so K must be smaller), while when the car is at a lower point, the kinetic energy is larger.
- Based on what we have written so far, we can conclude that the correct statement is:
B) The car at point C has less kinetic energy than the car at point B.
Because the car at point C is located at a higher point than point B, so the car at point C has larger potential energy than at point B, which implies that car at point C has less kinetic energy than the car at point B.
Answer:
(a) V1 = 8990.00 V
V2 = 8960.13 V
Explanation:
Parameters given:
q =3 mC
k = 8.99 * 10⁹ Nm²/C²
x1 = 3 m
x2 = 3.01 m
Electric potential is given as:
V = kq/r
Where
k = Coulombs constant
q = charge
r = distance
Potential at x1 is:
V1 = (8.99 * 10⁹ * 0.000003)/(3)
V1 = 8990.00V
Potential at x2 is:
V2 = (8.99 * 10⁹ * 0.003)/(3.01)
V2 = 8960.13 V
