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IrinaK [193]
3 years ago
7

Around the turn of the twentieth century, inventor Robert Shuman was engineering products that used energy directly from the Sun

to power motors and farms. He stated that coal and oil would eventually run out and that humans needed to learn how to use the more-abundant energy resource of the Sun. During which stage of technological design did Shuman identify that using oil and coal would be a problem? first second third fourth
Physics
1 answer:
MrRa [10]3 years ago
5 0

Answer: First stage

Explanation:

The four stages of technological design include:

• identifying a problem.

• Designing a solution.

• Implement, build, and test the design.

• Determine if solution met the need.

In this scenario, Robert Shuman identified the problem. This was depicted as he stated that coal and oil would eventually run out and that humans needed to learn how to use the more-abundant energy resource of the Sun,

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A girl drops a stone from the top a tower 45m tall. At the same time, a boy standing at the base of the tower, projects another
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Answer:

(i) The stones meet at 1.8 second

(ii) The point at which the stones meet, is 28.8 m above the base of the building and 16.2 m below the top of the building.

Explanation:

(i)

First we consider the stone dropped by the girl. We have data:

Vi = Initial Velocity of Stone = 0 m/s   (Since the stone was initially at rest)

t = Time Period

g = 10 m/s²

s₁ = Distance Covered by Stone

Using 2nd equation of motion, we get:

s₁ = Vi t + (0.5)gt²

s₁ = (0)(t) + (0.5)(10)t²

s₁ = 5t²   ----- equation (1)

Now, we consider the stone throne vertically upward by the boy. We have data:

Vi = Initial Velocity of Stone = 25 m/s

t = Time Period

g = - 10 m/s²   (negative sign due to upward motion)

s₂ = Distance Covered by Stone

Using 2nd equation of motion, we get:

s₂ = Vi t + (0.5)gt²

s₂ = (25)(t) + (0.5)(-10)t²

s₂ = 25t - 5t²   ----- equation (2)

At, the point where both the stones meet, the sum of distances covered by both stones must be equal to the height of building (i.e 45 m).

s₁ + s₂ = 45

using values from equation (1) and equation (2)

5t² + 25t - 5t² = 45

25t = 45

t = 45/25

<u>t =  1.8 sec</u>

(ii)

using this value of of t in equation (2)

s₂ = (25)(1.8) - (5)(1.8)²

<u>s₂ = 28.8 m</u>

using this value of of t in equation (1)

s₁ = (5)(1.8)²

<u>s₁ = 16.2 m</u>

<u>Hence, the point at which the stones meet, is 28.8 m above the base of the building and 16.2 m below the top of the building.</u>

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