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myrzilka [38]
3 years ago
7

PLEASE ANSWER ASAP!.!.!!.!!!!.!.!.

Physics
1 answer:
lbvjy [14]3 years ago
8 0
1. Most PE, because PE is directly proportional to distance (height)
Height: 100 meters
Speed: 0 mph

2. Most KE, because KE is directly proportional to speed
Height: 10 meters
Speed: 40 mph

3. Most TE, average KE
Height: 10 meters
Speed: 40 mph

4. The skater gains thermal energy as she goes down the slope, because the speed of the skater increases, so it increases the total kinetic energy of the particles, and makes them vibrate faster, resulting in a higher temperature.
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What causes competition among organisms?
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Both organisms attempt to use the same limited sources
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Why construction is present near the bulb ​
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The constriction causes the mercury column to break under tension, leaving a vacuum between the bottom of the column and that in the bulb, and the top of the column stays still at the position reached in the body - a "peak hold" system.

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4 years ago
An advantage of parallel circuits is that they A) stop transmitting all current if even one resistor breaks. B) form a single pa
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Parallel circuits allow current to flow even if some paths are cut, because a parallel circuit has more than one current-carrying path through it.

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What is the measurement of 29.46 cm, when rounded to three significant figures?
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29.5cm is the answer
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4 years ago
2. A student drives 7.8-km trip to school and averages a speed of
Alekssandra [29.7K]

Answer:

<em>The total time is: t=451.22 sec</em>

<em>The average speed is: V=34.57 m/s</em>

Explanation:

<u>Average speed</u>

The average speed is calculated by dividing the total distance traveled by an object (x) by the total time it took it to travel that distance (t).

\displaystyle V=\frac{x}{t}

Since the student makes the trip in two parts, we have to calculate the total distance and the total time.

We know the distance to school is 7.8 Km = 7,800 m. The student makes his way home over the same distance, thus the total distance is

x=2*7,800 m=15,600 m

The first trip to school was done at an average speed of v1=32.6 m/s. Knowing the distance and speed, we can calculate the time:

\displaystyle t1=\frac{x1}{v1}=\frac{7,800}{32.6}=239.26\ sec

The second trip back home was done at an average speed of v2=36.8 m/s. Let's calculate the second time:

\displaystyle t2=\frac{x2}{v2}=\frac{7,800}{36.8}=211.96\ sec

The total time is:

t=239.26\ sec+211.96\ sec=451.22\ sec

\boxed{t=451.22\ sec}

The average speed is:

\displaystyle V=\frac{15,600}{451.22}=34.57\ m/s

\boxed{\displaystyle V=34.57\ m/s}

6 0
3 years ago
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